Answer: a = 3∛2
<u>Step-by-step explanation:</u>
ab⁴ = 384 --> a = 384/b⁴
Substitute a = 384/b⁴ into the second equation to solve for "b".
a²b⁵ = 4608
![\bigg(\dfrac{384}{b^4}\bigg)^2\cdot b^5=4608\\\\\\\dfrac{147,456b^5}{b^8}=4608\\\\\\\dfrac{147,456}{b^3}=4608\\\\\\\dfrac{147,456}{4608}=b^3\\\\\\32=b^3\\\\\\\sqrt[3]{32} =b\\\\\\2\sqrt[3]{4} =b](https://tex.z-dn.net/?f=%5Cbigg%28%5Cdfrac%7B384%7D%7Bb%5E4%7D%5Cbigg%29%5E2%5Ccdot%20b%5E5%3D4608%5C%5C%5C%5C%5C%5C%5Cdfrac%7B147%2C456b%5E5%7D%7Bb%5E8%7D%3D4608%5C%5C%5C%5C%5C%5C%5Cdfrac%7B147%2C456%7D%7Bb%5E3%7D%3D4608%5C%5C%5C%5C%5C%5C%5Cdfrac%7B147%2C456%7D%7B4608%7D%3Db%5E3%5C%5C%5C%5C%5C%5C32%3Db%5E3%5C%5C%5C%5C%5C%5C%5Csqrt%5B3%5D%7B32%7D%20%3Db%5C%5C%5C%5C%5C%5C2%5Csqrt%5B3%5D%7B4%7D%20%3Db)
Substitute b = 2∛4 into the first equation to solve for "a".
ab⁴ = 384
a(2∛4)⁴ = 384
a = 384/(2∛4)⁴
a = 24/4∛4
= 6/∛4
= 6(∛2)/2
= 3∛2
Answer:
The weight of an apple is 150g rounded to the nearest 5g
what is the lower bound weight of the apple
what is the upper bound of the weight of the apple
Step-by-step explanation:
The weight of an apple is 150g rounded to the nearest 5g
what is the lower bound weight of the apple
what is the upper bound of the weight of the apple
It is to be solved by reminder thorem
f(x)/(x-k) will have reminder f(k),
so, f(2) = 5*(2^4) + 8 *(2^3) +4* (2^2) -5(2) +67
=5*16 + 8*8 +4*4 -5*2 +67
=80 + 64 + 16 -10 +67
= 217
Answer:
oof its been like 7 months and no one never answered
Step-by-step explanation:
so sad ;-;
The answer to the question is letter "D. Commutative Property of Addition". The property states that if there are two numbers which we may represent by a and b, the value of a + b is equal to the value of b + a. The given, 8 + 5.3 = 5.3 + 8 is an example of this property.
