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mr_godi [17]
4 years ago
6

A software distributor charges \$41$41dollar sign, 41 per license of a particular utility. The distributor offers a 10\%10%10, p

ercent discount on each license after the first 202020. How much would a business pay to buy 404040 licenses of the utility?
Mathematics
1 answer:
Alchen [17]4 years ago
3 0

Answer:

1558

Step-by-step explanation:

The first 202020 licenses cost full price, which is \$41$41dollar sign, 41 each. Thus, the first 202020 licenses cost a total of \$41 \cdot 20 = \$820$41⋅20=$820dollar sign, 41, dot, 20, equals, dollar sign, 820.

Hint #2

The remaining licenses have a 10\%10%10, percent discount. That means they cost 90\%90%90, percent of the full price. Let's write 90\%90%90, percent in its decimal form, 0.90.90, point, 9, in order to multiply.

\qquad 0.9 \cdot \$41 = \$36.900.9⋅$41=$36.900, point, 9, dot, dollar sign, 41, equals, dollar sign, 36, point, 90

Hint #3

There are 40 - 20 = 2040−20=2040, minus, 20, equals, 20 licenses at the reduced price of \$36.90$36.90dollar sign, 36, point, 90. Thus, the remaining 202020 licenses cost a total of \$36.90 \cdot 20 = \$738$36.90⋅20=$738dollar sign, 36, point, 90, dot, 20, equals, dollar sign, 738.

Hint #4

To find the cost for all 404040 licenses, let's add the costs of the full price and discounted licenses.

\qquad \$820 + \$738 = \$1558$820+$738=$1558dollar sign, 820, plus, dollar sign, 738, equals, dollar sign, 1558

Hint #5

The business would pay \$1558$1558dollar sign, 1558 to buy the licenses.

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The supreme choice pizza at Pizza Paradise contains 2 different meats and 4 different vegetables. The customer can select any on
oee [108]

Answer:

756

Step-by-step explanation:

This is a combination problem. Combination has to do with selection.

If we are to select r objects out of a oiil of n objects, this can be done in nCr number of ways as shown;

nCr = n!/(n-r)!r!

From the question, there are 4 meats and 9 vegetables to choose from. If the customer is to select 2 different meats and 4 different vegetables from the available ones, this can be done as shown

4C2 (selection of 2 different meats from 4meats) and 9C4(selection of 4 different vegetables from 9 total vegetables)

The total number of ways this can be done is 4C2 × 9C4

= 4!/(4-2)!2! × 9!/(9-4)!4!

= 4!/2!2! × 9!/5!4!

= 4×3×2!/2!×2 × 9×8×7×6×5!/5!×4×3×2

= 6 × 9×7×2

= 756ways

This means 756 different supreme choice pizzas can be made.

8 0
3 years ago
What is the slope-intercept equation of the line below?
Romashka-Z-Leto [24]
Sorry i can not see the line
7 0
3 years ago
Q7
Andrew [12]

Answer:  d = 4, n = 14

<u>Step-by-step explanation:</u>

S_n=\dfrac{a_1+a_n}{2}\cdot n

\text{Given:}\quad S_n=196, a_1=-12, a_n=40\\\\\\196=\dfrac{-12+40}{2}\cdot n\\\\392=28n\\\\14=n

a_{n}=a_1+d(n-1)\\a_{14}=a_1+d(14-1)\\40=-12+d(14-1)\\52 = 13d\\4=d

4 0
3 years ago
How much would $200 invested at 5% interest compounded monthly be
kicyunya [14]

Answer:

310.27

Step-by-step explanation:

3 0
3 years ago
What is the repulsive force between two pith balls that are 13.0 cm apart and have equal charges of −24.0 nC?
daser333 [38]

Answer:

The repulsive force is 3.067\times10^{-4}N.

Step-by-step explanation:

Consider the provided information.

The coulomb's law to calculate the repulsive force: F=\frac{kQ_1Q_2}{r^2}

Where the value of k is 9.00×10⁹ Nm²/C²

Substitute the respective values in the above formula.

F=\frac{9\times10^9\frac{N\cdot m^2}{c^2} \times(-24\times10^{-9}C)^2}{[(13 cm)(\frac{1m}{100cm} )]^2}

F=\frac{9\times10^9\frac{N\cdot m^2}{c^2} \times(-24\times10^{-9}C)^2}{(0.13 m)^2}

F\approx0.0003067N

F=3.067\times10^{-4}N

Hence, the repulsive force is 3.067\times10^{-4}N.

8 0
3 years ago
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