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mr_godi [17]
3 years ago
6

A software distributor charges \$41$41dollar sign, 41 per license of a particular utility. The distributor offers a 10\%10%10, p

ercent discount on each license after the first 202020. How much would a business pay to buy 404040 licenses of the utility?
Mathematics
1 answer:
Alchen [17]3 years ago
3 0

Answer:

1558

Step-by-step explanation:

The first 202020 licenses cost full price, which is \$41$41dollar sign, 41 each. Thus, the first 202020 licenses cost a total of \$41 \cdot 20 = \$820$41⋅20=$820dollar sign, 41, dot, 20, equals, dollar sign, 820.

Hint #2

The remaining licenses have a 10\%10%10, percent discount. That means they cost 90\%90%90, percent of the full price. Let's write 90\%90%90, percent in its decimal form, 0.90.90, point, 9, in order to multiply.

\qquad 0.9 \cdot \$41 = \$36.900.9⋅$41=$36.900, point, 9, dot, dollar sign, 41, equals, dollar sign, 36, point, 90

Hint #3

There are 40 - 20 = 2040−20=2040, minus, 20, equals, 20 licenses at the reduced price of \$36.90$36.90dollar sign, 36, point, 90. Thus, the remaining 202020 licenses cost a total of \$36.90 \cdot 20 = \$738$36.90⋅20=$738dollar sign, 36, point, 90, dot, 20, equals, dollar sign, 738.

Hint #4

To find the cost for all 404040 licenses, let's add the costs of the full price and discounted licenses.

\qquad \$820 + \$738 = \$1558$820+$738=$1558dollar sign, 820, plus, dollar sign, 738, equals, dollar sign, 1558

Hint #5

The business would pay \$1558$1558dollar sign, 1558 to buy the licenses.

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Answer:

21 cents

Step-by-step explanation:

All you have to do is divide 42/2

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3 years ago
The radioactive element americium-241 has a half-life of 432 years. How many years will it take a 10 gram mass of americium-241
geniusboy [140]
<h2>Answer: 816 years</h2>

This problem can be solved using the <u>Radioactive Half Life Formula: </u>

<u />

A=A_{o}.2^{\frac{-t}{h}}   (1)

Where:

A=2.7g is the final amount of the material

A_{o}=10g is the initial amount of the material

t is the time elapsed  (the quantity we are asked to find)

h=432y is the half life of americium-241

Knowing this, let's find t from (1):

2.7g=(10g).2^{\frac{-t}{432y}}  

\frac{2.7g}{10g}=2^{\frac{-t}{432y}}  

0.27g=2^{\frac{-t}{432y}}  

Applying natural logarithm in both sides:

ln(0.27g)=ln(2^{\frac{-t}{432y}})  

-1.309=-\frac{t}{432y}ln(2)  

-t=\frac{(-1.309)(432y)}{0.693}  

<u></u>

<u>Finally:</u>

t=816y

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3 years ago
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adoni [48]

The Correct Answer Should Be - 70

I Hope This Helps You!!!  :)

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Which equation represents the line through (4, -6) and (0, 2)?
lukranit [14]

Answer:

y=-2x+2

Step-by-step explanation:

Hi there!

Linear equations are typically organized in slope-intercept form: y=mx+b where <em>m</em> is the slope and <em>b</em> is the y-intercept (the value of y when x=0).

<u>1) Determine the slope (</u><u><em>m</em></u><u>)</u>

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Plug in the given points (4, -6) and (0, 2):

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y=-2x+b

<u>2) Determine the y-intercept (</u><u><em>b</em></u><u>)</u>

The y-intercept occurs when x=0. We are given that (0,2) falls on the line, so therefore, 2 is the y-intercept. Plug this into y=-2x+b:

y=-2x+2

I hope this helps!

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