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kodGreya [7K]
3 years ago
13

2x+5=3x+2 what does x equal

Mathematics
2 answers:
STALIN [3.7K]3 years ago
3 0

Answer:

x=3

Step-by-step explanation:

Step 1: Subtract 3x from both sides.

2x+5−3x=3x+2−3x

−x+5=2

Step 2: Subtract 5 from both sides.

−x+5−5=2−5

−x=−3

Step 3: Divide both sides by -1.

−x-1=- 3- 1

x=3

Answer:

x=3

Leni [432]3 years ago
3 0

Answer:

x = 3

Step-by-step explanation:

2x + 5 = 3x + 2

2x-3x = 2-5

-1x = -3

x = -3 ÷ ( -1 )

x = 3

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Solve for t in d = rt , if d = 57 and r = 30 t = ?
bulgar [2K]

Answer:

1.9

Step-by-step explanation:

First step would be to separate r from t

\frac{d}{r}  = t

Then just insert the numbers

\frac{57}{30}  = 1.9

6 0
4 years ago
Find the sum of 46 + 42 + 38 + ... + (-446) + (-450)46+42+38+...+(−446)+(−450)
JulijaS [17]

sum of sequence Find the sum of 46 + 42 + 38 + ... + (-446) + (-450) is -25,250

<u>Step-by-step explanation:</u>

We need to find sum of sequence  : 46 + 42 + 38 + ... + (-446) + (-450)

Given sequence is an AP with following parameters as :

a=46\\d=42-46=-4

So , Let's calculate how many terms are there as :

⇒ a_n=a +(n-1)d

⇒ -450=46 +(n-1)(-4)

⇒ -496=(n-1)(-4)

⇒ \frac{-496}{-4}=n-1

⇒ 124=n-1

⇒ n=125

Sum of an AP is :

⇒ S_n = \frac{n}{2}(2a+(n-1)d)

⇒ S_1_2_5 = \frac{125}{2}(2(46)+(125-1)(-4))

⇒ S_1_2_5 = \frac{125}{2}(-404)

⇒ S_1_2_5 =-25,250

Therefore , sum of sequence Find the sum of 46 + 42 + 38 + ... + (-446) + (-450) is -25,250

3 0
3 years ago
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Using the trend line y = 8x + 8, for the data shown, complete the residual table.
Anit [1.1K]

Answer:

-1,0,2,-2,0 in that order

Step-by-step explanation:

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Can you ummm finish the question

3 0
3 years ago
2x + 3y =10<br>x + y = 3 please do workings asap
kompoz [17]
This is system of Equations. 
<span>2x + 3y =10
x + y = 3 
</span>
x + y = 3 (multiply this by three) to get 3x + 3y = 9
2x + 3y =10
3x + 3y = 9 Subtract them

-1x = 1 
x=-1 
Now plug x back into the top equation and solve for y. 

I hope this helps! If not, let me know! Have a fantastical day!
5 0
4 years ago
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