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Julli [10]
3 years ago
8

Is this equation an infinite solution, no solution, or one solution?? 7(2+5x) = 3x + 14

Mathematics
1 answer:
shusha [124]3 years ago
7 0

Answer:

One Solution

Step-by-step explanation:

Once you solve the equation, you get 0 which satisfies for X, therefore it has a solution.

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Find tan(450-a), If <br><img src="https://tex.z-dn.net/?f=%20%5Ctan%28a%29%20%3D%20%20%5Cfrac%7B1%7D%7B2%7D%20" id="TexFormula1"
Inessa05 [86]

Answer:

tan(450-a)=5\sqrt{3}-8

Step-by-step explanation:

We know that:

tan(a-b)=\frac{tan(a)-tan(b)}{1+tan(a)tan(b)}

tan(450-a)=\frac{tan(450)-tan(a)}{1+tan(450)tan(a)}

Remember:

450°=360°+60°

and:

tan(a)=\frac{1}{2}

Thus:

tan(450-a)=\frac{tan(60)-tan(a)}{1+tan(60)tan(a)}\\\\

Then:

tan(450-a)=5\sqrt{3}-8

4 0
2 years ago
Delta Math! Please help.
vodka [1.7K]

Answer:

x = 1.5\sqrt{3}

Step-by-step explanation:

using the sine ratio in the right triangle and the exact value

sin60° = \frac{\sqrt{3} }{2} , then

sin60° = \frac{opposite}{hypotenuse} = \frac{x}{3} = \frac{\sqrt{3} }{2} ( cross- multiply )

2x = 3\sqrt{3} ( divide both sides by 2 )

x = 1.5\sqrt{3}

6 0
2 years ago
Read 2 more answers
A boutique marks up a $55 painting 18%. Find the new price.
Ede4ka [16]

Answer:

$9.9

Step-by-step explanation:

3 0
2 years ago
Convert this decimal into its fractional<br> form, simplified completely.<br> 0.650
podryga [215]

Answer:

13/20

Step-by-step explanation:

0.650 /1

0.650 × 100

1 × 100   =  

65 /100

65 ÷ 5

100 ÷ 5  =  

13 /20

4 0
2 years ago
A population of monkeys' tail lengths is normally distributed with a mean of 25 cm with a standard deviation of 8 cm. I am prepa
Crank

Answer:

<em>The probability that the mean of my sample will be between 24 and 25 cm</em>

<em>P(24 ≤X⁻≤25) = 0.4772</em>

Step-by-step explanation:

<u><em>Step(i)</em></u>:-

<em>Given mean of the Population  'μ'= 25c.m</em>

<em>Given standard deviation of the Population 'σ' = 8c.m</em>

<em>Given sample size 'n' = 256</em>

<em>Let X₁ = 24</em>

<em></em>Z_{1}  = \frac{x_{1}-mean }{\frac{S.D}{\sqrt{n} } } = \frac{24-25}{\frac{8}{\sqrt{256} } } =  -2<em></em>

<em>Let X₂ = 25</em>

<em></em>Z_{2}  = \frac{x_{2}-mean }{\frac{S.D}{\sqrt{n} } } = \frac{25-25}{\frac{8}{\sqrt{256} } } = 0<em></em>

<u><em>Step(ii)</em></u><em>:-</em>

<em>The probability that the mean of my sample will be between 24 and 25 cm</em>

<em>P(24 ≤X⁻≤25) = P(-2≤ Z ≤0)</em>

                     = P( Z≤0) - P(Z≤-2)

                     = 0.5 + A(0) - (0.5- A(-2))

                     = A(0) + A(2)        ( ∵A(-2) =A(2)

                     = 0.000+ 0.4772

                     = 0.4772

<u><em>Final answer</em></u>:-

<em>The probability that the mean of my sample will be between 24 and 25 cm</em>

<em>P(24 ≤X⁻≤25) = 0.4772</em>

                     

4 0
3 years ago
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