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2 years ago

Please please help me please please I’m begging you

Mathematics

1 answer:

viktelen [127]2 years ago

7 0

Answer:

Step-by-step explanation:

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What is the method to the problem

madreJ [45]

I think it might be the 3rd one.

Someone correct me if I'm wrong please.

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4 years ago

What's an equation that represents the number of teaspoons, t, contained in a cup, C?

strojnjashka [21]

Answer:

Step-by-step explanation:

t=C/ c

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c=quantity in a teaspoon

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3 years ago

Walter bought 500 marbles at the swap meet. Two-fifths of them

MrRissso [65]

Step-by-step explanation:

2/5 of marbles are blue

= 3/5 of marble are not blue.

Number of non-blue marbles = 500 * (3/5) = 300.

300 marbles are not blue.

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3 years ago

Suppose h(x)=3x-2 and j(x) = ax +b. Find a relationship between a and b such that h(j(x)) = j(h(x))

sergejj [24]

Answer:

$\displaystyle a = \frac{1}{3} \text{ and } b = \frac{2}{3}$

Step-by-step explanation:

We can use the definition of inverse functions. Recall that if two functions, f and g are inverses, then:

$\displaystyle f(g(x)) = g(f(x)) = x$

So, we can let j be the inverse function of h.

Function h is given by:

$\displaystyle h(x) = y = 3x-2$

Find its inverse. Flip variables:

$x = 3y - 2$

Solve for y. Add:

$\displaystyle x + 2 = 3y$

Hence:

$\displaystyle h^{-1}(x) = j(x) = \frac{x+2}{3} = \frac{1}{3} x + \frac{2}{3}$

Therefore, a = 1/3 and b = 2/3.

We can verify our solution:

$\displaystyle \begin{aligned} h(j(x)) &= h\left( \frac{1}{3} x + \frac{2}{3}\right) \\ \\ &= 3\left(\frac{1}{3}x + \frac{2}{3}\right) -2 \\ \\ &= (x + 2) -2 \\ \\ &= x \end{aligned}$

And:

$\displaystyle \begin{aligned} j(h(x)) &= j\left(3x-2\right) \\ \\ &= \frac{1}{3}\left( 3x-2\right)+\frac{2}{3} \\ \\ &=\left( x- \frac{2}{3}\right) + \frac{2}{3} \\ \\ &= x \stackrel{\checkmark}{=} x\end{aligned}$