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SpyIntel [72]
4 years ago
11

Solve sx+tx=r for x?

Mathematics
1 answer:
natulia [17]4 years ago
5 0

Answer:

x= r/s+t

Step-by-step explanation:

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3x/2 - 2 > 7
KiRa [710]

<span> 3x+2/2 = 7. First, multiply 2 to both sides and you get 3x+2=14. Then, just solve using backward PEMDAS. The answer is 4. </span>

<span></span>

8 0
3 years ago
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A document that is 35 in. By 40 in. Is redrawn at 1 1/2 scale and then redrawn at 1/4 scale. What are the final dimensions of th
Andru [333]
The dimension of the document is 35 inches by 40 inches.
It is redrawn at a scale of 1 1/2 or 3/2 or 1.5
The dimension will be:
35 * 1.5 = 52.5 in
40 * 1.5 = 60 in

Then redrawn again at 1/4 or 0.25
52.5 * 0.25 = 13.125 in
60 * 0.25 = 15 in

So the final dimensions of the drawing is 13.125 in by 15 in



5 0
3 years ago
Log (x) + log (x + 5) = log (6 x + 12) <br><br> I need the answer asap
kiruha [24]
It’s b I had it in my test
5 0
3 years ago
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If , find the value of 2 square root of 17-x = 2x-10, find the value of x/4.
ira [324]
2 \sqrt{17-x} =2x-10\ \ \ \ \Rightarrow\ \ \ D:(17-x \geq 0\ \ \ and\ \ \ 2x-10 \geq 0)\\.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x \leq 17\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \  \ \ x \geq 5\\\\.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ D=\\\\2 \sqrt{17-x} =2(x-5)\ /:2\\\\ \sqrt{17-x} =x-5\ \ \ \Rightarrow\ \ \ (\sqrt{17-x})^2 =(x-5)^2\\\\17-x=x^2-10x+25\\\\

x^2-9x+18=0\\\\ x^2-3x-6x+18=0\\\\x(x-3)-6(x-3)=0\\\\(x-3)(x-6)=0\ \ \ \ \Leftrightarrow\ \ \ (x-3=0\ \ \ \ or\ \ \ \ x-6=0)\\\\x=3\ \notin\ D\ \ \ \ \ \ \ \ \ \ \ x=6\ \in\ D\ \ \ \Rightarrow\ \ \  \frac{x}{4} = \frac{6}{4} =1.5\\\\Ans.\  \frac{x}{4} =1.5
7 0
3 years ago
What is the inverse of this function? f(x)=x−7
viva [34]

Answer:

<h3> f^−1(x) = x + 7</h3>

Step-by-step explanation:

Replace f(x) with y. y = x − 7

Interchange the variables.  x = y − 7

Solve for y.  y = x + 7

Solve for y and replace with f^−1 (x).  f^−1(x) = x + 7

I hope this helps have a great day :)

4 0
2 years ago
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