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SpyIntel [72]
3 years ago
11

Solve sx+tx=r for x?

Mathematics
1 answer:
natulia [17]3 years ago
5 0

Answer:

x= r/s+t

Step-by-step explanation:

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Let f(x)= 100 / −10+ e^ −0.1x . What is f(−6) ?
bija089 [108]

The value of f(-6) is -12.2

Explanation:

Given that the function f(x)=\frac{100}{-10+e^{-0.1\left(x\right)}}

We need to determine the value of f(-6)

The value of f(-6) can be determined by substituting the value for x=-6 in the function and simplify the function.

Hence, let us substitute x=-6 in the function, we get,

f(-6)=\frac{100}{-10+e^{-0.1\left(-6\right)}}

Let us apply the rule -\left(-a\right)=a , we get,

f(-6)=\frac{100}{-10+e^{0.1\left(6\right)}}

Multiplying the numbers, we get,

f(-6)=\frac{100}{-10+e^{0.6}}

The value of e^{0.6}=1.822

Substituting the value of e^{0.6}=1.822 , we get,

f(-6)=\frac{100}{-10+1.822}

Subtracting the denominator, we have,

f(-6)=\frac{100}{-8.178}

Dividing, we have,

f(-6)=-12.228

Rounding off to the nearest tenth, we have,

f(-6)=-12.2

Thus, the value of f(-6) is -12.2

4 0
2 years ago
What is the result of substituting for y in the bottom equation<br> y=x+3<br> y=x^2+2x-4
8_murik_8 [283]

The solutions are (2.1925, 5.1925) and (-3.1925, -0.1925)

<em><u>Solution:</u></em>

Given that,

y = x + 3 ------- eqn 1\\\\y = x^2 + 2x - 4  ----- eqn 2

<em><u>We have to substitute eqn 1 in eqn 2</u></em>

x + 3 = x^2 + 2x - 4

\mathrm{Switch\:sides}\\\\x^2+2x-4=x+3\\\\\mathrm{Subtract\:}3\mathrm{\:from\:both\:sides}\\\\x^2+2x-4-3=x+3-3\\\\\mathrm{Simplify}\\\\x^2+2x-7=x\\\\\mathrm{Subtract\:}x\mathrm{\:from\:both\:sides}\\\\x^2+2x-7-x=x-x\\\\\mathrm{Simplify}\\\\x^2+x-7=0

\mathrm{Solve\:with\:the\:quadratic\:formula}\\\\\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\mathrm{For\:}\quad a=1,\:b=1,\:c=-7\\\\x =\frac{-1\pm \sqrt{1^2-4\cdot \:1\left(-7\right)}}{2\cdot \:1}

x = \frac{-1 \pm \sqrt{ 1 + 28}}{2}\\\\x = \frac{ -1 \pm \sqrt{29}}{2}

x = \frac{ -1 \pm 5.385 }{2}\\\\We\ have\ two\ solutions\\\\x = \frac{ -1 + 5.385 }{2}\\\\x = 2.1925

Also\\\\x = \frac{ -1 - 5.385 }{2}\\\\x = -3.1925

Substitute x = 2.1925 in eqn 1

y = 2.1925 + 3

y = 5.1925

Substitute x = -3.1925 in eqn 1

y = -3.1925 + 3

y = -0.1925

Thus the solutions are (2.1925, 5.1925) and (-3.1925, -0.1925)

6 0
3 years ago
How many ways can Gary, Cayla, and
Kryger [21]

Answer:

6

Step-by-step explanation:

G,C,P

C,P,G

P,G,C

G,P,C

P,C,G

C,G,P

4 0
3 years ago
Simplify the expression -2+6.45z-6+(-3.25z)
erik [133]

Answer:

-8 + 3.2z

Step-by-step explanation:

  1. when there is a "+" in front of an expression in parentheses, the expression remains the same
  2. -2 + 6.45z - 6 - 3.25z
  3. calculate the difference

-8 + 6.45z - 3.25z

collect like terms

-8 + 3.2z

8 0
2 years ago
Two number have a sum of 71 and a difference of 37
larisa86 [58]
The right answer for the question that is being asked and shown above is that:

Two numbers have a sum of 71 and a difference of 37
x + y = 71
x - y = 37

So in order to get the two numbers, here it is:
x + y = 71
x - y = 37
------------
2x = 108
x = 54
y = 71 - 54
y = 17

<span>So the two numbers are 54 and 17</span>
6 0
2 years ago
Read 2 more answers
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