Ask question

Ask question

All categories

3 years ago

6

Kendrick is using the quadratic formula to solve the equation . Which statement best describes Kendrick’s work?

1 answer:

geniusboy [140]3 years ago

6 0

Answer: (–4)2 – 4(1)(0).

Step-by-step explanation:

The expression under the radical is correct as written. The expression under the radical should be –42 – 4(1). The expression under the radical should be –42 – 4(1)(0). The expression under the radical should be (–4)2 – 4(1)(0).

You might be interested in

Can someone check if my answer is right?

Stells [14]

Yes that’s correct!

8 0

3 years ago

The length of the top of a table is 4m greater than the width. The area is 96m^2. Find the dimensions of the table.

astraxan [27]

Let w be the width of the table. From this representation, the length of the table is now w + 4. The area of the rectangle is solved through the equation,
A = L x W
where L and W are length and width, respectively. Substituting the known values,
96 m² = (w + 4)(w)
w is 8. Therefore, the width of the table is 8 m and its length is 12 m.

4 0

3 years ago

Is the square root of negative 5 a rational irrational or imaginary

Travka [436]

I believe it is an imaginary number because imaginary numbers are square roots of negative numbers.

6 0

3 years ago

Read 2 more answers

Which equation is the inverse of y = 9x2 - 4?

m_a_m_a [10]

Answer:

The inverse will be:

$y' = \frac{\sqrt{x+4}}{3}$

Step-by-step explanation:

In order to find the inverse of the equation, we do a variable change, since we are finding the inverse, :

$f(x) = 9x^{2} - 4$

$y = 9x^{2} - 4$

$x = 9y' ^{2} - 4$

Now solve for y'.

First add 4 in both sides of the equation and change to the left y'.

$x + 4= 9y'^{2} - 4+4$

$9y'^{2}$ = x + 4

Second divide by 9

$9y'^{2}$ /9 = (x + 4)/9

$y'^{2}$ = (x + 4)/9

Now you will have to clear y, with the square root.

$[tex]y'^{\frac{2}{2}} = \sqrt{x + 4} / \sqrt{9}$ [/tex] =

Simplifying terms

$y' = \frac{\sqrt{x+4}}{3}$

$f^{-1}(x) = \frac{\sqrt{x+4}}{3}$

You can check the answer by doing the evaluation of the following equation:

(f o $f^{-1}$ ) (x)

substitute the equation for y' or inverse function $f^{-1}$

f( $\frac{\sqrt{x+4} }{3}$ )

Now substitue the value into f(x)

You will have

$= 9(\frac{\sqrt{x+4} }{3}} )^{2} - 4\\\\Solving\\\\9(\frac{{x+4} }{9}} ) - 4$

=x

5 0

3 years ago

two ferries start moving toward each other from opposite riverbanks, a and b. when they pass each other for the first time, the

Usimov [2.4K]

Let 'x' be the distance from THE far bank where 700 is the distance to the NEAR bank

boat one has travelled 700 (rate = 700/unit time) boat two has travelled x rate = x / unit time

boat one then travels x + 400 more and boat two travels 700 + (700+x -400) more when they meet

The time is the same rate x time = distance distance/rate = time equate the distances divided by the respective rates

(700 + x + 400)/700 = ( x + 700 + (700+x-400) )/x

1100x + x^2 = 1400x + 700000

x^2-300x -700000 = 0 quadratic formula yields x = 1000

One boat travels 700 the other 1000 whe they first meet.....width of river = 700+ 1000 = 1700 m

3 0

3 years ago