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Artemon [7]
3 years ago
7

Alice has a total of 12 dimes and nickels. She has 2 more nickels than dimes

Mathematics
1 answer:
valkas [14]3 years ago
6 0
This is a problem of system of linear equations in two variables. This concept of mathematics is very useful in real-life problems. You can solve a system by finding the solution. A solution of a system are the values of the variables that satisfies each equation in the system. So by knowing these concepts we can get a system of equation by analyzing each statement step by step, that is:

1. Alice has a total of 12 dimes and nickels.

Let the variables:

D: Dimes \\ N:Nickles

1st. Equation:

D+N=12

<span>2. She has 2 more nickels than dimes

2nd Equation:

N=D+2

Therefore our system of linear equations is:

</span>(1) \ D+N=12 \\ (2) \ N=D+2 \\ \\ Substituting \ (2) \ in \ (1): \\ D+(D+2)=12 \therefore 2D=10 \therefore D=5 \\ \\ Solving \ for \ N \ in \ (2): \\ N=5+2=7

Conclusion:

<span>Alice has 5 dimes and 7 nickels. </span>
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Answer:

7.5 ?

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
In the barn, there are horses and chickens. There are 11 heads and 32 legs altogether. How many chickens are there?
Masteriza [31]

Answer:

6 Chickens

Step-by-step explanation:

Let  H represent the number of horses and  C represent the number of chickens. Since there are 32 legs altogether this means that on equation to use would be given by:

2C  +  4 H  =  32     (Eq. 1)

Another equation can be made from the fact that there are 11 heads or 11 animals altogether which can be written as:

C  +  H  =  11    (Eq. 2)

From Eq. 2, solve for the number of chickens:

C  +  H  =  11

C   =  11  - H    (Eq. 3)

Substituting Eq. 3 in Eq. 1, the number of horses can be determined:

2 C  +  4 H  =  32

2 ( 11  −  H )  +  4 H  =  32

22   −  2 H  +  4 H  =  32

2H  =  32  − 22

2 H  = 10

H = 5               Eq.4

Putting Eq.4 in Eq.1

2C + 4*5 =  32

2C = 32 - 20

2C = 12

C = 12/2

C = 6

8 0
3 years ago
Find the value for d<br> 2d - 5 = 17
Ann [662]
2d-5=17

2d=17+5

2d=22
— —
2 2

d=11
4 0
3 years ago
Can u please answer this question
Paha777 [63]
One Way:
We can change the mixed number to a decimal for comparing.

1\frac{1}{4} m = \frac{5}{4} m = 1.25 m

1.4 m     >    1.25 m
Darren   >     Luke

Darren's jump was higher by (1.4-1.25) 0.15 m

Or another way change the decimal to a fraction and the mixed to an improper fraction too.

1\frac{1}{4} = \frac{5}{4} (Luke)
1.4 = \frac{7}{5}                               (Darren)
We need a common denominator to compare
\frac{5*5}{4*5}       (Luke)
\frac{7*4}{5*4}       (Darren)
\frac{25}{20}          (Luke)
\frac{28}{20}          (Darren)

\frac{28}{20}  >   \frac{25}{20}
        Darren           >            Luke
  
By:
\frac{28}{20} - \frac{25}{20} = \frac{3}{20}
Which is also by 0.15 m
Darren jumps higher and by 0.15 m
3 0
3 years ago
How I can solve this
gavmur [86]

Answer:

\boxed{\textrm{B)}\qquad y>4}.

Step-by-step explanation:

We start by subtracting 1 from both sides of the second inequality:

2x > 5 \iff 2x - 1 > 5 - 1 \iff 2x - 1 > 4.

Therefore, we conclude that:

y > 2x - 1 > 4 \implies y > 4.

Therefore, every point that satisfies the system has a y-coordinate greater than 4.

7 0
3 years ago
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