Answer:
The short answer is there isn’t.
Start by writing each of these as an expression:
x * y = 60
x + y = 7
Next, solve each for the same variable; in this case, y:
(x * y) / x = 60 / x
.: y = 60 / x
(x + y) - x = 7 - x
.: y = 7 - x
Next, replace y of the second expression to the first
y = 60 / x & y = 7 - x
.: 7 - x = 60 / x
Now, solve for x:
(7 - x) * x = (60 / x) * x
.: x * 7 - x^2 = 60
This is quadratic, so write it in the form of ax2 + bx + x = 0
(-1)x^2 + (7)x + (-60) = 0
.: a = -1, b = 7, c = -60
Finally solve for b:
x = (-b +- sqrt(b^2 - 4*a*c)) / 2a
.: x = (-7 +- sqrt(7^2 - 4*-1*-60)) / (2 * -1)
.: x = (-7 +- sqrt(49 - 240)) / -2
.: x = (-7 +- sqrt(-191)) / -2
The square root of a negative value is imaginary and thus there’s no real answer to this problem.
Answer:
Find the value of x(attachment 11)
6)
7x = 6 + 5x
7x - 5x = 6
2x = 6
x = 6/2 = 3
7)
30 = 4x + 6
4x = 30 - 6 = 24
x = 24/4 = 6
8)
2(x + 4) =16
x + 4 = 16/2 = 8
x = 8 - 4 = 4
9)
7 + 5x = 3x + 13
5x - 3x = 13 - 7
2x = 6
x = 6
<u>Find the area(From attachment 2)</u>
1) Area = 4* 5 = 20
2)Area = 7 * m = 7m
3). Area = 3* a = 3a
4). Area = x*x = x²
5). Area = 4*x + 3* 4 = 4x + 12
6). Area = 7*a + 7*9 = 7a + 63
7). Area = 3x*x + 2*3x = 3x² + 6x
<u>expression of line segment</u>
8) x + 9
9). x + 4
10). a + 2
Answer:
(4, 1 )
Step-by-step explanation:
Given the 2 equations
2x + 3y = 11 → (1)
x - 3y = 1 → (2)
Adding (1) and (2) term by term will eliminate the term in y
3x = 12 ( divide both sides by 3 )
x = 4
Substitute x = 4 into either of the 2 equations and evaluate for y
Substituting into (1)
2(4) + 3y = 11
8 + 3y = 11 ( subtract 8 from both sides )
3y = 3 ( divide both sides by 3 )
y = 1
Solution is (4, 1 )