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devlian [24]
3 years ago
10

Rewrite the equation by completing the square. x^2 + 2x – 48 = 0

Mathematics
1 answer:
slamgirl [31]3 years ago
3 0

Answer:

(x+1)^2 = 49

x = 6                 x = -8

Step-by-step explanation:

x^2 + 2x – 48 = 0

Add 48 to each side

x^2 + 2x =48

Take the coefficient of x

2

Divide by 2

2/2=1

Square it

1^2 =1

x^2 + 2x +1=48+1

x^2 +2x+1 = 49

(x+1)^2 = 49

Take the square root of each side

sqrt((x+1)^2) =±sqrt( 49)

x+1 = ±7

Subtract 1 from each side

x+1-1 = -1  ±7

x = -1+7          x = -1 -7

x = 6                 x = -8

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Solve the system of inequalities:<br> 6y≥42<br> 4y+12≤0
Hatshy [7]

Answer:

no solution

Step-by-step explanation:

6y≥42

Divide each side by 6

6y/6≥42/6

y≥7

Then solve the second one

4y+12≤0

Subtract 12 from each side

4y+12-12≤0-12

4y ≤-12

Divide each side by 4

4y/4 ≤-12/4

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8 0
3 years ago
PLEASE HELP!!!
vovikov84 [41]

Answer:

Both the parts of this question require the use of the "Intersecting Secant-Tangent Theorem".

Part A

The definition of the Intersecting Secant-Tangent Theorem is:

"If a tangent segment and a secant segment are drawn to a circle from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment."

This, when applied to our case becomes, "The length of the secant RT, times its external segment, ST, equals the square of the tangent segment TU".

Mathematically, it can be written as:

Part B

It is given that RT = 9 in. and ST = 4 in. Thus, it is definitely possible to find the value of the length TU and it can be found using the Intersecting Secant-Tangent Theorem as:

Thus,  

Thus the length of TU=6 inches

6 0
3 years ago
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