no because mathematically 30X10=300 not 900 its would have to be 30X30 to get the product of 900 so therefore no your statement is incorrect
Answer:
.
Step-by-step explanation:
It is given that a number, x, rounded to 2 significant figures is 1300.
It is possible if,
1. The value of x is greater than of equal to 1250 and less than or equal to 1300.
i.e.,
...(1)
2. The value of x is greater than of equal to 1300 and less than 1350.
i.e.,
...(2)
On combining (1) and (2), we get

1350 is not included in the error interval for x.
Interval notation is
.
Therefore, the error interval for x is
.
Answer:
20
Step-by-step explanation:
We can set up a percentage proportion to find the value of x.

Now we cross multiply:

Hope this helped!
Answer:
18,176
Step-by-step explanation:
Figure out an easier thing to do: 1000 - 2021 = 9,797.
Therefore, our answer will be like 9999999999999999999999997979. Out of all of these digits, there are only 2 that arent nines. We know the amount of digits since it's 10^2021 power. We will have one less since we are subtracting 2021. Therefore, 2020 digits in total. Now we know of those 2020 digits, 2 of them are 7, therefore 2018 of them are 9s. That means do 2018(9) + 2(7) = 14 + 18,162 = 18,176.