All categories

3 years ago

Domain: -00 < x < 00Range: pi/2 ≤ y ≤ pi/2 what is tan^ -1 (1) =

Mathematics

1 answer:

e-lub [12.9K]3 years ago

6 0

Answer:

π/4

Step-by-step explanation:

Other options for arctan(1) is 5π/4 + nπ, where n is a whole number, but they are all outside the Range.

You might be interested in

What is the value of the discriminant, b2 − 4ac, for the quadratic equation 0 = x2 − 4x + 5, and what does it mean about the num

Aleksandr-060686 [28]

So discriminant gives us 3 possibilites connected with result of the equation b^2-4ac. If it is bigger than zero, there are 2 solutions, if answer is exactly 0, then there is one answer and if the number is lower than 0, there are no solutions.

Discriminant of your quadratic equation is (-4)^2-4*1*5=16-20=-4, so there are no solutions.

3 0

3 years ago

Read 2 more answers

The graph is of y = f(x) is shown below. What are all of the real solutions of f(x) = 0?

Reika [66]

The real solutions of f(x) = 0 is; x = -8, 0 and 4

<h3>How to find the roots of a polynomial graph?</h3>

When talking about real solutions of a polynomial, we are simply referring to the values of x that make the polynomial f(x) = 0.

Now, in a polynomial graph as attached, the real solutions are the roots and they are the values of x where the curve crosses the x-axis.

From the given graph, the real solutions are at x = -8, 0 and 4

Thus, we conclude that the real solutions of f(x) = 0 is; x = -8, 0 and 4

Read more about Polynomial roots graph at; brainly.com/question/14625910

#SPJ1

8 0

1 year ago

This is the graph of y = sin(x). Does anyone know the second part?

Alborosie

Answer:

The resulting graph is $y = 5\cdot \sin x$ .

Step-by-step explanation:

The resulting function is of the form:

$y = A\cdot \sin x + k$

Where:

$x$ - Independent variable, dimensionless.

$y$ - Dependent variable, dimensionless.

$A$ - Amplitude, dimensionless.

$k$ - Midpoint value, dimensionless.

The sine function is bounded, between -1 and 1, and must be multiplied by a stretch factor. That is: $A > 0$ . According to the graph, the function is bounded between 5 ( $y_{max}$ ) and -5 ( $y_{min}$ ), and the midpoint value ( $k$ ) is 0. The amplitude is determined by the following calculation:

$A = \frac{y_{max}-y_{min}}{2}$

If $y_{min} = -5$ and $y_{max} = 5$ , then:

$A = 5$

The resulting graph is $y = 5\cdot \sin x$ .

6 0

3 years ago

Your beginning balance on your lunch account is $55. You buy lunch for 1.75 everyday and sometimes buy a snack for $0.85 after 2

Agata [3.3K]

Multiply 1.75 with 25 because you bought snacks everyday and then you’re left with 11.25

Now subtract .20 because you were left with that on day 26 and you get 11.05

Lastly you divide 11.05 with .85 to see how many snacks you bought

ANSWER IS 13 snacks

3 0

3 years ago

If point B is at 0, then what are the values of points A and C?

Sunny_sXe [5.5K]

Answer:

Since the line is not scaled, then how do we know for sure. But, we do know that point A is the opposite of point C. For example, if C = 150, then A = -150

Step-by-step explanation:

Since the line is not scaled, then how do we know for sure. But, we do know that point A is the opposite of point C. For example, if C = 150, then A = -150

8 0

2 years ago

Domain: -00 < x < 00Range: pi/2 ≤ y ≤ pi/2 what is tan^ -1 (1) =​

Domain: -00 < x < 00Range: pi/2 ≤ y ≤ pi/2 what is tan^ -1 (1) =