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3 years ago

Domain: -00 < x < 00Range: pi/2 ≤ y ≤ pi/2 what is tan^ -1 (1) =

Mathematics

1 answer:

e-lub [12.9K]3 years ago

6 0

Answer:

π/4

Step-by-step explanation:

Other options for arctan(1) is 5π/4 + nπ, where n is a whole number, but they are all outside the Range.

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Given directed line segment QS , find the coordinates of R

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Answer:

The answer is below

Step-by-step explanation:

The question is not complete, what are the coordinates of point Q and R. But I would show how to solve this.

The location of a point O(x, y) which divides line segment AB in the ratio a:b with point A at ( $x_1,y_1$ ) and B( $x_2,y_2$ ) is given by the formula:

$x=\frac{a}{a+b}(x_2-x_1)+x_1\\ \\y=\frac{a}{a+b}(y_2-y_1)+y_1$

If point Q is at ( $x_1,y_1$ ) and S at ( $x_2,y_2$ ) and R(x, y) divides QS in the ratio QR to RS is 3:5, The coordinates of R is:

$x=\frac{3}{3+5}(x_2-x_1)+x_1=\frac{3}{8}(x_2-x_1)+x_1\\ \\y=\frac{3}{3+5}(y_2-y_1)+y_1=\frac{3}{8}(y_2-y_1)+y_1$

Let us assume Q(−9,4) and S(7,−4)

$x=\frac{3}{8}(7-(-9))+(-9)=\frac{3}{8}(16)-9=-3\\\\y=\frac{3}{8}(-4-4)+4=\frac{3}{8}(-8)+4=1$

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Step-by-step explanation:

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Step-by-step explanation:

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3 years ago

Domain: -00 < x < 00Range: pi/2 ≤ y ≤ pi/2 what is tan^ -1 (1) =​

Domain: -00 < x < 00Range: pi/2 ≤ y ≤ pi/2 what is tan^ -1 (1) =