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3 years ago

Two and two fifths divided by one and a half

Mathematics

1 answer:

worty [1.4K]3 years ago

6 0

Answer:

8/5 or 1 3/5

Step-by-step explanation:

2 2/5 = 12/5

1 1/2 = 3/2

Now that we have fractions that are easier to divide, one must understand that the opposite of dividing is multiplying. So if you multiply 12/5 by the reciprocal* of 3/2, which would be 2/3, you would get your answer so...

12 3 12 2 24 8 3

— ÷ — = — × — = — = — <em>or</em> 1 —

5 2 5 3 15 5 5

*the reciprocal is the opposite of the fraction you have. So the denominator would become the numerator, and vise versa.

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baherus [9]

The probability that a student participates in both sports and drama is $0.14$ .

<h3>What is the formula for P(AUB), where A and B are any two events?</h3>

If $A$ and $B$ are any two events, then the probability of the joint event $(A\cup B)$ is given by the following formula: $P(A\cup B)=P(A)+P(B)-P(A\cap B)$

Given that 42% of the students participate in sports and 25% of the students participate in drama and 53% of the students participate in either sports or drama.

Suppose $S$ denotes that "a student participates in sports" and $D$ denotes that "a student participates in drama".
So, we have $P(S)=\frac{42}{100}=0.42$ , $P(D)=\frac{25}{100}=0.25$ , $P(S\cup D)=\frac{53}{100}=0.53$ .

We want to find the probability that a student participates in both sports and drama i.e., we want to find $P(S\cap D)$ .

By the above formula, we obtain:

$P(S\cup D)=P(S)+P(D)-P(S\cap D)\\\Longrightarrow P(S\cap D)=P(S)+P(D)-P(S\cup D)\\\Longrightarrow P(S\cap D)=0.42+0.25-0.53\\\therefore P(S\cap D)=0.14=\frac{14}{100}$

Therefore, the probability that a student participates in both sports and drama is $0.14$ .

To learn more about probability, refer: brainly.com/question/24756209

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