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2 years ago

1. Write a polynomial function in factored form with zeros at -2, 5, and 6.

Mathematics

1 answer:

Hatshy [7]2 years ago

4 0

Answer:

f(x) = (x + 2) (x − 5) (x − 6)

Step-by-step explanation:

f(x) = (x − (-2)) (x − 5) (x − 6)

f(x) = (x + 2) (x − 5) (x − 6)

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When estimated, is 6.2-4.96 greater or less than 1?

pogonyaev

6.2 - 4.96 = 1.24 > 1
1.24 is greater than 1.

7 0

3 years ago

URGENT!!!!!

Anna11 [10]

h=20w

in one week hector works 20 hours

in two hector works 40 etc

h = hours and w = weeks. the money is just extra information.

h=20w works because if it has been two weeks we substitute the w with the number 2 and can solve

h=20(2)

h=20x2

h=40

This proves that the equation is true

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3 years ago

Solution for 8x-3(2x-4)=3(x-6)

NNADVOKAT [17]

The solution is x=30

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3 years ago

In one year, the student enrollment increased from 560 to 588. This was an increase of what percent?

sergiy2304 [10]

Answer:

5% Increase

Step-by-step explanation:

560 * 0.05 = 28

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8 0

3 years ago

Read 2 more answers

The equation of a circle is x^2+y^2-2x +6y-6=0. Find the center and radius of the circle by completing the square.you must inclu

zavuch27 [327]

Answer:

The center of the circle is at;

$(1,-3)$

The radius of the circle is;

$r=4$

Explanation:

Given the equation of circle;

$x^2+y^2-2x+6y-6=0$

we want to re-write it in the form;

$(x-h)^2+(y-k)^2=r^2$

where;

$\begin{gathered} (h,k)\text{ is the center of the circle} \\ r\text{ is the radius} \end{gathered}$

Applying Completing the square method;

$\begin{gathered} x^2+y^2-2x+6y-6=0 \\ x^2-2x+1+y^2+6y+9=6+1+9 \\ (x-1)^2+(y+3)^2=16 \\ (x-1)^2+(y+3)^2=4^2 \end{gathered}$

comparing the derived equation to the general form we have;

$\begin{gathered} h=1 \\ k=-3 \\ r=4 \end{gathered}$

Therefore;

The center of the circle is at;

$(1,-3)$

The radius of the circle is;

$r=4$

6 0

8 months ago