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timofeeve [1]
2 years ago
13

Asssssssssaaaaaappppppppp

Mathematics
1 answer:
BigorU [14]2 years ago
7 0

Answer:

7

Step-by-step explanation:

Just multiply all numbers together.

Plz give me brainliest

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Jimmy’s age is one year less than the sum of the ages of his siblings Serena and Tyler. Which equation represents Jimmy’s age?
andriy [413]
I think it is d because the questions says: j-1+s+t 
3 0
3 years ago
This may prove to be somewhat tricky.) Suppose that we have 10 coins, which are weighted so thatwhen flipped theith coin shows h
timama [110]

Answer:

2/10

Step-by-step explanation:

Probability of getting head on i'th coin = i/10

Probability Pr of getting head on 2nd coin (Event A) = 2 / 10

Probability Pr of getting head on 1st coin (Event B) = 1/10

Probability A given B = Pr (A/B) = Pr (A∩B) / Pr B ;

where A∩B = Pr (A & B) = Pr A X Pr B

Putting in above formula :

Pr (A/B) = <u>[(</u>1/10)x(2/10<u>)]</u>  / 1/10

= 2/10

4 0
3 years ago
What is a true statement about negative exponents?
Nadya [2.5K]

Answer:

Raising something to a negative exponent is just taking the reciprocal of the amount.

Step-by-step explanation:

Let's assume that you wanted to know what x^{-2} is.

To find it, you would take the reciprocal of the x amount. So x^{-2} becomes \frac{1}{x^{2}}.

This works because of the nature of exponents. Exponents represent the number of times you are multiplying a value by itself. So a^{3} would be equal to a · a · a. To increase the exponent, you increase the number of times the value is multiplied by itself: To increase a^{3} to a^{5}, you would have to multiply a with a^{3} two more times (a · a · a · a · a). To decrease the exponent, you must divide the value by itself. So to decrease a^{5} to a^{2}, you would have to divide a^{5} by a 3 times.

If the exponent is 0, the value is equal to 1. But you can still decrease the exponent into negative numbers. You just divide 1 by a the desired amount of times: \frac{1}{a^{3}} means that you are dividing 1 by a 3 times.

Hope this helps.

3 0
2 years ago
What is the exact distance from (–1, 4) to (6, –2)? (4 points) units units units units
irina1246 [14]

Answer:

\sqrt{85}

Step-by-step explanation:

Calculate the distance d using the distance formula

d = √ (x₂ - x₁ )² + (y₂ - y₁ )²

with (x₁, y₁ ) = (- 1, 4) and (x₂, y₂ ) = (6, - 2)

d = \sqrt{(6+1)^2+(-2-4)^2}

  = \sqrt{7^2+(-6)^2}

  = \sqrt{49+36}

  = \sqrt{85} ← exact distance

4 0
3 years ago
Question 3 (Multiples and Factors] Three numbers are given below. Use prime factorisation to determine the HCF and LCM 1848 132
Ilia_Sergeevich [38]

Prime factorization involves rewriting numbers as products

The HCF and the LCM of 1848, 132 and 462​ are 66 and 1848 respectively

<h3>How to determine the HCF</h3>

The numbers are given as: 1848, 132 and 462

Using prime factorization, the numbers can be rewritten as:

1848 = 2^3 * 3 * 7 * 11

132 =  2^2 * 3 * 11

462 = 2 * 3 * 7 * 11

The HCF is the product of the highest factors

So, the HCF is:

HCF = 2 * 3 * 11

HCF = 66

<h3>How to determine the LCM</h3>

In (a), we have:

1848 = 2^3 * 3 * 7 * 11

132 =  2^2 * 3 * 11

462 = 2 * 3 * 7 * 11

So, the LCM is:

LCM = 2^3 * 3 * 7 * 11

LCM  = 1848

Hence, the HCF and the LCM of 1848, 132 and 462​ are 66 and 1848 respectively

Read more about prime factorization at:

brainly.com/question/9523814

4 0
2 years ago
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