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stealth61 [152]
3 years ago
6

The average cost to produce a video game can be computed using the equation C(x) = 6000/x-50. What range of videos games should

be produced to keep the cost at most $6.00? Please write your answer in complete sentences.
PLEASE HELP
Mathematics
2 answers:
MAXImum [283]3 years ago
8 0

Answer:

We need to produce 1,050 copies

Step-by-step explanation:

So the equation we are working with is,

C(x) = 6000/x-50

Assuming that x is the amount of video game copies produced, and C(x) being the final price per copy. Then we can replace C(x) with $6.00 and solve for x. This will give us the amount of video game copies that need to be produced in order to keep the price at or below $6.00.

6 = \frac{6000}{x-50} ... multiply both sides by x-50

6x-300 = 6000 ...... add 300 on both sides

6x = 6300  ..... divide by 6 on both sides

x = 1050

So after solving for x , we can see that we need to produce 1,050 copies in order to keep the price at or under $6.00

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

hammer [34]3 years ago
3 0

so, whatever the cost C(x) will be, it must be 6 or less than 6, what would the quantity x for such?


\bf C(x)=\cfrac{6000}{x-50}\implies \stackrel{C(x)}{6}\stackrel{\stackrel{\textit{less than 6 or equals to 6}}{\downarrow }}{\le}\cfrac{6000}{x-50}\implies x-50\le \cfrac{6000}{6}
\\\\\\
x-50\le 1000\implies x\le 1050\impliedby \begin{array}{llll}
\textit{\underline{x} quantity must be 1050}\\
\textit{or less, or between 0 - 1050}
\end{array}

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Step-by-step explanation:

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