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swat32
3 years ago
14

The number of boxes of cookies sold by Sarah was 50 fewer than the number of boxes of cookies sold by Keiko. The number of boxes

of cookies sold by Imelda was
22 greater than the number sold by Keiko. Write an algebraic expression for each quantity. Use x to represent the unknown value.
the number of boxes of cookies sold by Sarah
= the number of boxes of cookies sold by Keiko
= the number of boxes of cookies sold by Imelda
Mathematics
1 answer:
RSB [31]3 years ago
5 0

Answer:

abcdefghijklmnopqrstuvwxyz

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Answer: this is how i feel about the answers A 80% b 0% c 90% d 0%

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The answer is 14.33333 but you will have to round which you will just have 14.3
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If two points have the same __ or ____ coordinate, then they lie under same ____of the coordinate plane
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7 0
3 years ago
What are 3 consecutive numbers that is the sum of -27.please be right.use odd numbers
qaws [65]
You're asking for three consecutive odd numbers, then
Let, the numbers = x, x+2, x+4

It is given that, x + x+2+ x+4 = -27
3x + 6 = -27
3x = -27 - 6
x = -33/3
x = -11
Then, x+2 = -9 & x+4 = -7

In short, Your Numbers would be: -7, -9,-11

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6 0
3 years ago
The first three terms of a sequence are given. Round to the nearest thousandth (if necessary).
BabaBlast [244]

Step-by-step explanation:

the introduction of a fraction tells us that we are dealing with multiplications, and therefore a geometric sequence (where every new term is created by multiplying the previous term by a constant factor, the ratio r).

I think your teacher made a mistake, or you made one when typing the question in here.

there is no factor r that creates

15×r = 9

and

9×r = 5/27

it would mean that

15 × r² = 5/27

r² = 5/27 / 15 = 5/27 × 1/15 = 5/405 = 1/81

r = 1/9

but 15 × 1/9 = 5 × 1/3 = 5/3 is NOT 9

and 9 × 1/9 = 9/9 = 1 is NOT 5/27

so, this can't be right.

on the other hand

15 × r = 9

r = 9/15 = 3/5

and then

9 × 3/5 = 27/5

so, either the sequence should have been

15, 5/3, 5/27

or (and I suspect this to be true)

15, 9, 27/5

under that assumption we have

s1 = 15

r = 3/5

sn = sn-1 × r = s1 × r^(n-1) = 15 × (3/5)^(n-1)

s10 = 15 × (3/5)⁹ = 15 × 19683/1953125 =

= 3 × 19683/390625 = 59049/390625 =

= 0.15116544 ≈ 0.151

6 0
2 years ago
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