A. 41 + 16=57 40+17= 57
b. 79 + 14=93 80+13= 93
c. 580+355=935 600+335=935
d. 174+620=794 194+600=794
e. 378+210=588 388+200=588
Here you go, hope this helps! :)
8 ÷ 2 = 4
4× 15 = 60
y = 60
Answer:
Yumiko should multiply the other equation by 3.
If she adds the two equations she would be left with the variable 'x'.
Step-by-step explanation:
Given the two equations are as follows:
It is given that she multiplies the first equation by 6. Therefore, (1) becomes
Now, note that the sign of the variable 'y' is negative. So, if we make the co-effecient of 'y' equal in both the cases, add them it would result in the elimination of the variable 'y'.
The co-effecient of y in Equation (2) is 6. To make it 18 like it is in Equation (1), we multiply throughout by 3.
Therefore, Equation (2) becomes:
Now, we add Equation (a) and Equation (b).
Factor: 3
Equation: 27x = 126
Answer:
so that the trinomial can be factored: x^2+bx+15. Algebra -> Polynomials-and-rational-expressions -> SOLUTION: Find all integers b so that the trinomial can be factored: x^2+bx+15 Log On. Algebra: Polynomials, rational expressions
Step-by-step explanation:
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Answer:
Step-by-step explanation:
It is required to find the value of t for the given expression. The expression is :
It is simply based on calculations. Multiplying both equations by 7. We get :
On RHS, 7 will cancel out. Thus we get :
Since, 4 × 7 = 28
So, the value of t is .