All categories

2 years ago

Use the quadratic formula to solve 5x^2+2x-3

1 answer:

6 0

Assuming it equals 0
for
ax^2+bx+c=0
x= $\frac{-b+/- \sqrt{b^2-4ac} }{2a}$

given
5x^2+2x-3=0
a=5
b=2
c=-3

x= $\frac{-2+/- \sqrt{2^2-4(5)(-3)} }{2(5)}$
x= $\frac{-2+/- \sqrt{4+60} }{10}$
x= $\frac{-2+/- \sqrt{64} }{10}$
x= $\frac{-2+/- 8 }{10}$
x=(-2+8)/10 or (-2-8)/10
x=6/10 or -10/10
x=3/5 or -1

You might be interested in

PLEASE HELP WITH THESE TWO QUESTIONSSS 1. Which value is equivalent to sin20∘?

Nata [24]

Answer:

a) $\cos(70\degree)$

b) 12.72 units

Step-by-step explanation:

Recall that the sine and cosine are completed functions.

This means that: $\sin(x)=\cos(90-x)$

$\sin(20\degree)=\cos(90-20)$

$\sin(20\degree)=\cos(70\degree)$

Recall that: sine ratio is opposite/hypotenuse

$\sin 58=\frac{|PQ|}{15}$

This implies that:

$|PQ|=15\sin 58$

$|PQ|=15(0.848)$

$|PQ|=12.72$

4 0

3 years ago

Need answer this urgent and fast

Karo-lina-s [1.5K]

Answer:

Step-by-step explanation:

Hey There!

so this is a parallelogram so opposite angles are congruent

So basically what i am saying is that angle P is congruent to angle R

So we need to solve for x

We know that angle P and angle Q are supplements meaning that they will add up to 180

so we setup the equation

$180=3x+5+8x-12\\$

step 1 combine like terms

$3x+8x=11x\\5-12=-7$

now we have

180=11x-7

step 2 add 7 to each side

180+7=187

-7+7 cancels out

now we have

187=11x

step 2 divide each side by 11

187/11=17

x=17

now we plug in 17 to (3x+5) to get the value of angle R

17x3=51

51+5=56

therefore m∠R = 56

5 0

2 years ago

Please help with this MATH question. I would appreciate it, it is the only one I need help with. SOLVING A SYSTEM INCLUDING LINE

makkiz [27]

Answer:

see below and attached

Step-by-step explanation:

To solve a system of quadratic equations:

Equal the equations then rearrange so that it is set to zero.
Use the quadratic formula to solve.

I have done this (see attached workings) but cannot get any of the solutions you've provided. I have even graphed the two functions, and the points of intersection concur with my workings (see attached graph).