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Y_Kistochka [10]
3 years ago
5

An orchard has 4 rows of apple tree with 12 trees in each row. There are also 6 rows of pear trees with 15 trees in each row. Ho

w many apple and pear trees are in the orchard
Mathematics
2 answers:
Harrizon [31]3 years ago
8 0
The formula to this question is the amount of rows and how many fruit are in each row.
So 4x12=48
There are 48 apples in the apple orchard 
and 6x15=90
so 90+48=138
There are 138 pieces of fruit in total
Snezhnost [94]3 years ago
8 0

Answer:

48 apple trees and 90 pears trees

Step-by-step explanation:

Number of rows of apple trees in an Orchard= 4 rows

Number of trees in each row= 12 trees

Total number of apple trees= Total number of rows × total number of trees

Total number of apple trees= 4×12

Total number of apple trees= 48 trees

Number of rows of pear trees in an Orchard= 6 rows

Number of trees in each row= 15 trees

Total number of apple trees= Total number of rows × total number of trees

Total number of apple trees= 6×15

Total number of apple trees= 90 trees

Hence, the correct answer is 48 apple trees and 90 pear trees or 138 tress

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A gate is made up of a rectangle and a semicircle, as shown. Find the area of the gate. Use 3.14 for .Round your answer to the n
allochka39001 [22]

Answer:

<em>797.0ft²</em>

Step-by-step explanation:

<u>Find a related diagram attached</u>

Area of the gate = Area of the semicircle + Area of the Rectangle

Area of the semicircle = πr²/2

r is the radius

From the diagram, radius r = 20/2 = 10ft

Area of the semicircle = 3.14(10)²/2

Area of the semicircle = 3.14(100)/2

Area of the semicircle = 314/2

Area of the semicircle = 157ft²

Area of the rectangle = Length * Width

Area of the rectangle = 20*32

Area of the rectangle = 640ft²

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Area of the gate = 797ft²

<em>Hence the area of the gate is 797.0ft²</em>

7 0
3 years ago
Is this correct? If not plz get answers 25points!!!
katen-ka-za [31]

That is correct.

Sqrt 5 x sqrt20

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2 years ago
What’s the domain and range of:<br> log(√(2x-1) + 3 )<br> Please explain how you got it too!!
Radda [10]

Two main facts are needed here:

1. The logarithm \log x, regardless of the base of the logarithm, exists for x>0.

2. The square root \sqrt x exists for x\ge0.

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By (2) we know that \sqrt{2x-1} exists if 2x-1\ge0, or x\ge\dfrac12.

By (1), we know that \log(\sqrt{2x-1}+3) exists if \sqrt{2x-1}+3>0, or \sqrt{2x-1}>-3. But as long as the square root exists, it will always be positive, so this condition will always be met.

Ultimately, then, we only require x\ge\dfrac12, so the function has domain \left[\dfrac12,\infty).

To determine the range, we need to know that, in their respective domains, \sqrt x and \log x increase monotonically without bound. We also know that x=\dfrac12 at minimum, at which point the square root term vanishes, so the least value the function takes on is \log3. Then its range would be [\log3,\infty).

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