Answer:
Table is attached with values, but answers are:
(0, 0) (1, 3) (2, 6) (3, 9)
Step-by-step explanation:
y = 3x
Substitute all values.
y = 3(0)
y = 0
0, 0
y = 3(1)
y = 3
1, 3
y = 3(2)
y = 6
2, 6
y = 3(3)
y = 9
3, 9

- What is the solution to the inequality -3x-42>3 ?


Add 42 to both sides.

Add 3 and 42 to get 45.

Divide both sides by -3. As -3 is <0, the inequality direction has changed.

Divide 45 by -3 to get -15.

For domain 2x sqrt(2+x)>0
x>0,2+x>0,x>-2 combining
we get x>2
f'(x)=[1/{2x sqrt(2+x)}][{2x/(2 sqrt(2+x))}+2 sqrt(2+x)]
-3 < x < -8
There is no value of c that is greater than -3 AND less that -8