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3 years ago

14

Two parallel wires carry a current in the same direction. there is ___________ between the wires.

1 answer:

Arte-miy333 [17]3 years ago

7 0

The correct answer is "an attractive force" between the wires.

Let's see why. Assume we have wire A on the left and wire B on the right, and that the current in both wires go upward. First, let's find the direction of the magnetic field produced by wire A at wire B: by using the right-hand rule, we see that since the current (the thumb) goes upward, the magnetic field (given by the other fingers) at wire B is directed inside the paper.
Then we can apply again the right-hand rule to see what is the force on wire B. The index gives the direction of the current (upward), the middle finger the direction of the magnetic field (inside the paper), and the thumb gives the direction of the force: to the left, so toward wire A. This means the force is attractive. (you can re-do the procedure on wire A, and you will find the force on wire A is directed toward wire B)

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Open the attached file. It shows 2 waves (a blue one and an orange one) that are moving through the same medium at the same time

Taya2010 [7]

The diagram is labelled to DRAW the RESULTANT wave and LABEL the areas of interference with CI, DI and/or points of TDI.

<h3>What is refraction?</h3>

When a light ray falls on the interface of two medium like air and water, then the portion of light is reflected and another portion of the light is refracted into the water medium. The angle of incidence is equal to the angle of reflection but the angle of incidence is larger then the angle of refraction.

Open the attached file. It shows 2 waves (a blue one and an orange one) that are moving through the same medium at the same time.

Thus, the diagram is labelled.

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3 0

2 years ago

The age of a piece of wood from an archeological site is to be determined using the Carbon-14 method. The activity of the sample

Bezzdna [24]

Answer:

4589.05 year

Explanation:

The relation of activity is given by $A=A_0e^{\lambda t}$ we have given $\frac{A}{A_0}=0.574$

Half life $T=5730\ years$

We know that half life $T=\frac{0.693}{\lambda }$

$\lambda =\frac{0.693}{5730}=1.2094\times 10^{-4}\ per\ year$

So $0.574=e^{-1.2094\times 10^{-4}t}$

$e^{1.2094\times 10^{-4}t}=\frac{1}{0.574}=1.742$

${1.2094\times 10^{-4}t}=ln1.742=0.555$

$t=\frac{0.555}{1.2094\times 10_{-4}}=4589.05\ year$

7 0

3 years ago

Below is an oscilloscope trace from an AC supply. Calculate the frequency of the supply if each horizontal division represents 0

GuDViN [60]

Answer:

20 hertz of frequency produced.

Explanation:

$\boxed{frequency = \frac{1}{period} }$

Here we will find frequency and period should be in second, here given: 0.05 seconds

using the formula:

$\boxed{frequency = \frac{1}{0.05} }$

$\boxed{frequency =20}$

8 0

3 years ago

How are air temperature and air pressure related?

geniusboy [140]

Answer: Whenever the temperature is high, the air pressure is low.

Explanation:As the temperature rises, the air gets heated, expands, and becomes lighter. … As a result, the air pressure in such areas decreases.

5 0

2 years ago

a car takes off from rest and covers a distance of 80m on a straight road in 10s.calculate the magnitude of its acceleration

olasank [31]

$▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪$

Here's the solution :

Let's find the final velocity :

$\dfrac{displacement}{time}$

$\dfrac{80}{10}$

$8 \: \: ms {}^{ - 1}$

Initial velocity (u) = 0 (cuz it started from rest)

Final velocity (v) = 8 m/s

Time taken (t) = 10 sec

now, we know that :

$acceleration = \dfrac{v - u}{t}$

$\dfrac{8 - 0}{10}$

$\dfrac{8}{10}$

$0.8 \: \: m {s}^{ - 2}$

Acceleration = 0.8 m/s²

7 0

3 years ago