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3 years ago

1) The current in a light bulb is 0.335 Amps. How long does it take for a total charge of 2.76 C to

Physics

1 answer:

uysha [10]3 years ago

7 0

Answer:

Time=8.23880597 seconds

Explanation:

Quantity of charge(q)=2.76c

Current(I)=0.335A

Time(t)=?

t=q/I

t=2.76/0.335

t=8.23880597seconds

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Two spherical asteroids have the same radius R. Asteroid 1 has mass M and asteroid 2 has mass 1.97·M. The two asteroids are rele

nekit [7.7K]

Answer:

$0.536\sqrt{\frac{GM}{R}}$

Explanation:

We are given that

Mass of one asteroid 1, $m_1=M$

Mass of asteroid 2, $m_2=1.97 M$

Initial distance between their centers,d=13.63 R

Radius of each asteroid=R

d'=R+R=2R

Initial velocity of both asteroids

$u=0$

We have to find the speed of second asteroid just before they collide.

According to law of conservation of momentum

$(m_1+m_2)u=m_1v_1+m_2v_2$

$(M+1.97 M)\times 0=Mv_1+1.97Mv_2$

$Mv_1=-1.97 Mv_2$

$v_1=-1.97v_2$

According to law of conservation of energy

$Gm_1m_2(\frac{1}{d'}-\frac{1}{d})=\frac{1}{2}m_1v^2_1+\frac{1}{2}m_2v^2_2$

$GM(1.97M)(\frac{1}{2R}-\frac{1}{13.63R})=\frac{1}{2}M(-1.97v_2)^2+\frac{1}{2}(1.97M)v^2_2$

$1.97M^2G(\frac{13.63-2}{27.26R})=\frac{1}{2}Mv^2_2(3.8809+1.97)$

$1.97MG(\frac{11.63}{27.26 R})=\frac{1}{2}(5.8509)v^2_2$

$v^2_2=\frac{1.97GM\times11.63\times 2}{27.26R\times 5.8509}$

$v_2=\sqrt{\frac{1.97GM\times11.63\times 2}{27.26R\times 5.8509}}$

$v_2=0.536\sqrt{\frac{GM}{R}}$

Hence, the speed of second asteroid = $0.536\sqrt{\frac{GM}{R}}$

8 0

3 years ago

What is the unit of work? (select all that apply) *

galina1969 [7]

Answer:

Joule is the answer

Please give me brainleast

4 0

3 years ago

A cyclist moving with a constant velocity of 6.0 m/s forward passes a car that is just starting. If the car has a constant accel

sergiy2304 [10]

After 6 seconds, the car will surpass the cyclist.

<h3><u>Explanation:</u></h3>

The speed of the cyclist = 6 m/s.

Let after time t sec, the car will overtake the cyclist.

So, distance covered by the cyclist in t sec = 6t m

Initial velocity of the car is 0 m/s, because the car is just starting.

Acceleration of the car = $2 m/s^2$ .

Final velocity of the car =6 m/s.

So to cover the distance 6t, the time required by the car = $\frac{1}{2} \times a \times t^2 = \frac{1}{2} \times 2 \times t^2$

$6t = \frac{1}{2} \times 2 \times t^2\\6t = t^2$

t =6 sec

So, after 6 seconds, the car will surpass the cycle.

6 0

3 years ago

Identify the area where convection is taking place.

Softa [21]

In this area the convection is taking place inside the water which is inside the utensils.

<u>Explanation:</u>

Convection is the type of heat transfer method which is usually taking place through the liquid and gases. In this convection process, the liquid acts as the medium for the heat transfer.
From the given picture we can see both convection and conduction. The conduction process which occurs in the solid objects. Here the heat is directly given to the pan which is a solid conductor so the pan conducts the heat.
Inside the pan there happens to be the liquid which favors the convection process and again the eggs are heated by the conduction process as the outer part of the egg is solid.

8 0

4 years ago

Read 2 more answers

The equation T squared = A cubed shows the relationship between a planet’s orbital period, T, and the planets mean distance from

Nataly [62]

Answer:

orbital period increased by a factor of 2.83 unit

Explanation:

Given.

planet’s orbital period, T, and the planets mean distance from the sun, A, in astronomical units, AU

T²= A³

If A is increased by a factor of 2 , .

Then T will be increase with the factor of √2³ = 2.83

3 0

3 years ago

Read 2 more answers