Answer:
The distance is 300 m.
Explanation:
Given that,
Time = 30 s
Speed = 80 m/s
Distance = 1200 m
Speed of smaller plane = 40 m/s
We need to calculate the acceleration
Using equation of motion

Put the value in the equation



We need to calculate the distance
Using equation of motion

Put the value in the equation



Hence, The distance is 300 m.
The transit method requires watching the light output of a star over long periods of time. A transit occurs when the planet crosses in front of its star from earths point of view. Since there is a small object (the planet) now blocking some of the star, it appears to dim a little bit for a while until the planet passes. If we are in a position where that occurs regularly (most paths of planets do not happen to be on the line of sight between earth and their star) we can deduce the period of orbit. From the amount of dimming and the period you can estimate the mass
Answer:
The solution was to implement an absolute magnitude scale to provide a reference between stars. To do so, astronomers calculate the brightness of stars as they would appear if it were 32.6 light-years, or 10 parsecs from Earth.
Explanation:
the path of an electron around the nucleus of an atom