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Anastasy [175]
3 years ago
15

Would lifting a 1 kg block 1 meter off the ground be work? Yes or No

Physics
1 answer:
JulsSmile [24]3 years ago
8 0

Answer:

NO

Explanation:

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A yacht is pushed along at a constant velocity by the wind. The wind force is 180N at an angle of 25 degrees to the direction of
damaskus [11]
The parallel component is given by
F=180cos(25)=163.14N
4 0
4 years ago
An acorn with a mass of 0.300 kilograms falls from a tree. What is its kinetic energy when it reaches a velocity of 5.oo m/s?
vladimir1956 [14]

Answer: 3.75 joules

Explanation:

Given that:

Mass of acorn = 0.300 kilograms

velocity = 5.oo m/s

Kinetic energy = ?

Since, kinetic energy is the energy possessed by a moving object, its value depends on the mass M and velocity V of the acorn.

Thus, Kinetic energy = 1/2 x mv^2

= 1/2 x 0.300kg x (5.00m/s)^2

= 0.5 x 0.3kg x (5.00m/s)^2

= 0.15 x (5.00m/s)^2

= 3.75 joules

Thus, the kinetic energy of the falling acorn is 3.75 joules

5 0
3 years ago
Which of the following is represented by the letter A in the diagram below?
Kruka [31]

We have that the letter A in the diagram below given as

Amplitude

Option A

<h3>Amplitude</h3>

Question Parameters:

Amplitude

Crest

Trough

Wavelength

Generally, the amplitude of a wave is the maximum  displacement of the wave in the medium from its initial position.

Amplitude is denoted with the letter A

Therefore,Amplitude

Option A

For more information on displacement visit

brainly.com/question/989117

6 0
2 years ago
A large piece of jewelry has a mass of 130.8 g. A graduated cylinder initially contains 47.7 mL water. When the jewelry is subme
Shkiper50 [21]

Answer: The density of this piece of jewelry is 8.90g/cm^3

Explanation:

To calculate the density, we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}

Mass of piece of jewellery = 130.8 g

Density of piece of jewellery = ?

Volume of piece of jewellery =( 62.4-47.7 ) ml = 14.7 ml = 14.7cm^3   1cm^3=1ml

Putting values in above equation, we get:

\text{Density of piece of jewellery}=\frac{130.8g}{14.7cm^3}=8.90g/cm^3

Thus density of this piece of jewelry is 8.90g/cm^3

8 0
3 years ago
A 1.5m wire carries a 7 A current when a potential difference of 68 V is applied. What is the resistance of the wire?
PSYCHO15rus [73]

Working...

length of wire L = 1.5 m

current I = 7 A

potential difference V = 68 Volt

According to Ohm's Law

V = IR

R = V/I

R = 68/7

R = 9.7 Ω

3 0
4 years ago
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