Answer:
5730 years
Explanation:
The half life of carbon-14 is 5730 years. If 50% of the carbon-14 remains, then exactly 1 half life has passed.
The half-life equation is:
A = A₀ (½)^(t / T)
where A is the remaining amount,
A₀ is the initial amount,
t is time,
and T is the half life.
In this case, A = ½ A₀ and T = 5730.
½ A₀ = A₀ (½)^(t / 5730)
½ = (½)^(t / 5730)
1 = t / 5730
t = 5730
Answer:
w = 0.173 N
Explanation:
The weigh of any object is computed by multiplying its mass to the acceleration of gravity, so we need to find the gravity on that planet in order to compute the weigh we want.
The ball has a mass of 0.1 kg and its released from a height of 10 m, therefore it is in a free fall motion with gravity acting as a constant acceleration on the body, we can use the equations for free fall movement in order to determine the value for this acceleration:
y(t) = v_0 * t + y_0 - 0.5 * g * t^2
y(t) is the position in the end of the movement, when t = 3.4 s, so y(t) = 0 m.
v_0 is the initial velocity, in this case v_0 = 0 m/s.
y_0 is the initial position of the ball, in this case it is 10 m.
g is the gravity that we want to know.
Applying these values in the equation we have:
0 = 0*(3.4) + 10 - 0.5*g*(3.4)^2
0 = 10 - 0.5*11.56*g
0 = 10 -5.78*g
5.78*g = 10
g = 1.73 m/s^2
Then we can use this value to find out the weigh of the ball in that planet:
w = g*m = 0.1*1.73 = 0.173 N
200 MeV of energy
E1/E2=7.61=8
U is equal to 1 kilogram or 1000 g.
There are 6.02310 23 atoms in one mole, or 235 g, of uranium. Therefore, 6.02310 23 atoms are present in 1000 g of 92/235 U.
It is understood that one atom releases 200 MeV of energy during its fission.
As a result, the energy released from the fission of one kilogram of 92/235 is given by E 2 = 6.02310 23 1000200/235 =5.10610 26 MeV E1/E2=7.61=8
In light of this, the energy released during the fusion of one kilogram of hydrogen is roughly eight times greater than the energy generated during the fission of one kilogram of uranium.
To learn more about Fission please visit -
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