1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ohaa [14]
4 years ago
15

Then standard toolbar appears whenever you select text true or fals

Computers and Technology
1 answer:
OverLord2011 [107]4 years ago
6 0
False nothing appears. <span />
You might be interested in
In the Happy Valley School System, children are classified by age as follows: less than 2, ineligible 2, toddler 3-5, early chil
sasho [114]

// C++ switch

// It can also be used for JAVA, C#

switch(age){

// here age will be sent by the function in which it is used

// case to check the age<2

case(age<2 && age>0):

// printing the line

cout<<"ineligible";

// case to check the age ==2

case(age==2):

// printing the line

cout<<"toddler";

// case to check 3-5

case(age>=3 && age<=5):

cout<<"early childhood";

// case to check 6-7

case(age==6 || age==7):

cout<<"young reader";

//case to check 8-10

case(age>=8 && age<=10):

cout<<"elementary";

// case to check 13

case(age==13):

cout<<"impossible";

//case tocheck 14-16

case(age>=14 && age<=16):

cout<<"high school";

// case to check 17 or 18

case(age==17 || age==18):

cout<<"scholar";

//case to check >18

case(age>18);

cout<<"ineligible";

// default case

default:

cout<<"Invalid age";

}

Read more on Brainly.com - brainly.com/question/12981906#readmore

5 0
3 years ago
The purpose of this assignment is to determine a set of test cases knowing only the function’s specifications, reported hereaf
Nesterboy [21]

Answer:

The program is written using PYTHON SCRIPT below;

N=int(input(" Enter number of Rows you want:"))

M=[] # this for storing the matrix

for i in range(N):

l=list(map(int,input("Enter the "+str(i+1)+" Row :").split()))

M.append(l)

print("The 2D Matrix is:\n")

for i in range(N):

print(end="\t")

print(M[i])

W=[] # to store the first non zero elemnt index

T=[] # to store that value is positive or negative

L=len(M[0])

for i in range(N):

for j in range(L):

if (M[i][j]==0):

continue

else:

W.append(j) # If the value is non zero append that postion to position list(W)

if(M[i][j]>0): #For checking it is positive or negative

T.append(+1)

else:

T.append(-1)

break

print()

print("The first Non Zero element List [W] : ",end="")

print(W)

print("Positive or Negative List [T] : ",end="")

print(T)

Explanation:

In order for the program to determine a set of test cases it takes in input of 2D matrix in an N numbet of rows.

It goes ahead to program and find the column index of the first non-zero value for each row in the matrix A, and also determines if that non-zero value is positive or negative. The If - Else conditions are met accordingly in running the program.

5 0
3 years ago
By negatively influencing data collection, ____ can have a detrimental effect on analysis.
oksano4ka [1.4K]

By negatively influencing data collection, <u>bias</u> can have a detrimental effect on analysis.

In statistical analysis, bias occurs when the data collected is not a true representation of the group under study. Bias occurs due to various mistakes or errors that occur at the time of data collection and sampling.

If a particular data is negatively influenced, then this means that there will be a bias in the expected results. Such a case can be highly detrimental especially if the studies would be implemented for a human issue.

The bias produced by a negative influence will cause errors in the analysis of the data leading to an overall wrong result.

To learn more about bias, click here:

brainly.com/question/24491228

#SPJ4

7 0
1 year ago
Given a floating-point formal with a k-bit exponent and an n-bit (fraction, write formulas for the exponent E, significant M, th
ANEK [815]

Answer:

A) Describe the number 7.0 bit

The exponential value ( E ) = 2

while the significand value ( M ) = 1.112  ≈ 7/4

fractional value ( F )  = 0.112

And, numeric value of the quantity ( V )  = 7

The exponent bits will be represented  as :  100----01.

while The fraction bits will be represented  as : 1100---0.

<u>B) The largest odd integer that can be represented exactly </u>

The integer will have its exponential value ( E ) = n

hence the significand value ( M )

=  1.11------12 = 2 - 2-n

also the fractional value ( F ) =  

0.11------12 = 1 – 2-n

Also, Value, V = 2n+1 – 1

The exponent bits  will be represented  as follows:  n + 2k-1 – 1.

while The bit representation for the fraction will be as follows: 11---11.

<u>C) The reciprocal of the smallest positive normalized value </u>

The numerical value of the equity ( V ) = 22k-1-2

The exponential value ( E )  = 2k-1 – 2

While the significand value ( M )  = 1

also the fractional value ( F ) = 0

Hence The bit representation of the exponent will be represented as : 11---------101.

while The bit representation of the fraction will be represented as : 00-----00.

Explanation:

E = integer value of exponent

M = significand value

F = fractional value

V = numeric value of quantity

A) Describe the number 7.0 bit

The exponential value ( E ) = 2

while the significand value ( M ) = 1.112  ≈ 7/4

fractional value ( F )  = 0.112

And, numeric value of the quantity ( V )  = 7

The exponent bits will be represented  as :  100----01.

while The fraction bits will be represented  as : 1100---0.

<u>B) The largest odd integer that can be represented exactly </u>

The integer will have its exponential value ( E ) = n

hence the significand value ( M )

=  1.11------12 = 2 - 2-n

also the fractional value ( F ) =  

0.11------12 = 1 – 2-n

Also, Value, V = 2n+1 – 1

The exponent bits  will be represented  as follows:  n + 2k-1 – 1.

while The bit representation for the fraction will be as follows: 11---11.

<u>C) The reciprocal of the smallest positive normalized value </u>

The numerical value of the equity ( V ) = 22k-1-2

The exponential value ( E )  = 2k-1 – 2

While the significand value ( M )  = 1

also the fractional value ( F ) = 0

Hence The bit representation of the exponent will be represented as : 11---------101.

while The bit representation of the fraction will be represented as : 00-----00.

8 0
3 years ago
Minor changes to objects which only take effect at render time are called:
Ad libitum [116K]

Answer:

modifiers

Explanation:

The modifiers are the change that is minor with respect to the objects that have an impact at the render time

Therefore as per the given situation, the last option is correct as it fits to the current scenario

And, the rest of the options would be incorrect

The same is to be considered and relevant

Hence, the modifier is the correct option

7 0
3 years ago
Other questions:
  • When creating a professional presentation, how many typefaces are recommended at the most?
    5·1 answer
  • What type of hard drive is in original xbox?
    6·1 answer
  • If you sort by Last Name, Ascending, which of the following last names would come first in the list?
    12·1 answer
  • Does learning swift is hard? more than android?
    13·1 answer
  • Jean has created a database to track all of this month’s family meals. To find an entry for lasagna, what would should Jean do?
    6·1 answer
  • A ________ algorithm is a method of locating a specific item of information in a larger collection of data.
    8·1 answer
  • What is GIGO ?<br>plz answer me​
    7·1 answer
  • Every finger has a key it should be resting on when you are not typing<br> 1. False<br> 2. True
    12·2 answers
  • When would it be appropriate to run MS Office or Adobe on the Windows OS server ?
    10·1 answer
  • To behave ethically means
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!