Answer: is this a real question but I think it would be Ip address hope this helps :)))
Explanation:
Answer:
Java code is given below
Explanation:
import java.util.Random;
class Die{
private int sides;
public Die(){
sides = 6;
}
public Die(int s){
sides = s;
}
public int Roll(){
Random r = new Random();
return r.nextInt(6)+1;
}
}
class DieRoll{
public static void main(String[] args) {
Die die = new Die();
int arr[] = new int[6];
for(int i=0; i<6; i++)
arr[i] = 0;
for(int i=0; i<100; i++){
int r = die.Roll();
arr[r-1]++;
}
for(int i=0; i<6; i++)
System.out.println((i+1)+" was rolled "+arr[i]+" times.");
}
}
Change the line in word, it basically returns
The best type of chart to illustrate the daily water intake that you would be taking in the next three months would be (A) Line.
Line is most suitable because it will show the progression – be it the increase and decrease – of your water intake clearly, compared to using bar, which is more suitable if you would like to contrast your water intake with your soda intake, for example.
JAVA programming was employed...
What we have so far:
* Two 2x3 (2 rows and 3 columns) arrays. x1[i][j] (first 2x3 array) and x2[i][j] (second 2x3 array) .
* Let i = row and j = coulumn.
* A boolean vaiable, x1rules
Solution:
for(int i=0; i<2; i++)
{
for(int j=0; j<3; j++)
{
x1[i][j] = num.nextInt();
}
}// End of Array 1, x1.
for(int i=0; i<2; i++)
{
for(int j=0; j<3; j++)
{
x2[i][j] = num.nextInt();
}
}//End of Array 2, x2
This should check if all the elements in x1 is greater than x2:
x1rules = false;
if(x1[0][0]>x2[0][0] && x1[0][1]>x2[0][1] && x1[0][2]>x2[0][2] && x1[1][0]>x2[1][0] && x1[1][1]>x2[1][1] && x1[1][2]>x2[1][2])
{
x1rules = true;
system.out.print(x1rules);
}
else
{
system.out.print(x1rules);
}//Conditional Statement
