The issue arises because the string you are trying to print is not a string, rather a float value. Item1, item2 and item3 are strong values (if you type some alphabets in it and not just numbers), but itemonecost, itemtwocost, and itemthreecost are explicitly type casted to float. In line 22, 23, and 24 you’re trying to print a float, by adding it with the string. One cannot add numbers to string. Rather you can type cast the itemcost to string while printing.
Add str(itemonecost) instead of itemonecost in print statement. Do this for other float variables too.
However do note that there are multiple ways to correct this issue, and I’ve just pointed one out.
This depends on what program you're using. Some programs can only read certain files exclusive to that program, such as .psd files can usually only be read in Photoshop or other adobe programs. Many fields of work (Journalism, the Arts, Design, etc.) ask for .psd files to be converted to either .png, .jpg, or .tiff so that it can be seen on many other platforms.
For images especially, files are more compatible either on a program or printed. for example, .png files are good for storing color data from computer to computer, but if you print a .png file, the quality is poor. hence it's recommended to save files you want to print for designs as .jpeg, because .jpeg can more easily be printed and will then be presented at a high quality.
Sometimes color quality changes depending on CMYK as well but that's a whole other ball of wax.
Answer: C. Differential backup
Explanation: There are several ways od ensuring the preservation and storage of data even cases of disaster, one of such ways is data data mirroring which allows data to be replicated or copied in real time and several backup options. In cases where there there is need to restore a server, the warm recovery site provides a data or disaster recovery option used to mitigate the effect of data loss on organization. In the absence of data mirroring, differential backup option, provides the quickest recovery option as it only requires changes in the data stored after the last full backup. These speed experieced should be expected due to the relatively low data been dealt with rather than the entire data.
