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Anastasy [175]
3 years ago
6

This year, Napa Corporation received the following dividends: KLP Inc (a taxable Delaware corporation in which Napa holds an 8%

stock interest) - $55,000 Gamma Inc (a taxable Florida corporation in which Napa holds a 90% stock interest) - $120,000 Napa and Gamma do not file a consolidated tax return. Compute Napa's dividends-received deduction. Please show complete calculation.
Business
1 answer:
murzikaleks [220]3 years ago
7 0

Answer:

$147,500

Explanation:

Computation of Napa's dividends-received deduction

Napa is said to holds less than 20% stock interest in KLP Inc which means that the dividends received deduction in the case of dividends received from KLP would be 50%.

And in case of dividends received from Gamma, the dividends received deduction would be 100% reason been that KLP holds more than 80% of the stock interest in Gamma.

Hence:

Napa’s dividends-received deduction will be:

= ($55,000 x 50%) + $120,000

=$27,500 +$120,000

= $147,500

Therefore Napa's dividends-received deduction will be $147,500

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A 4-year project has an annual operating cash flow of $58,500. At the beginning of the project, $4,950 in net working capital wa
valina [46]

Answer:

Net   Cash flow   in year 4   $46,140<u> </u>

Explanation:

Cash flow represent the amount of cash revenue less out of pocket cash expenditures. Non-cash related items are not included.

Year    4                                               cash flow     ;

                                                                     $

Operating cash flow                               $58,500

Working capital recouped                     4,950

Scrap value                                            6,090    

Tax payable (40%*58500)                      <u>(23400 )</u>

  Net   Cash flow                            <u>      46,140 </u>

3 0
3 years ago
On October 1, 2014, Mann Company places a new asset into service. The cost of the asset is $80,000 with an estimated 5-year life
Lelu [443]

Answer:

The correct answer is A.

Explanation:

Giving the following information:

On October 1, 2014, Mann Company places a new asset into service. The cost of the asset is $80,000 with an estimated 5-year life and $20,000 salvage value at the end of its useful life.

Annual depreciation= (original cost - salvage value)/estimated life (years)

Annual depreciation= 60,000/5=12,000

3 months depreciation= 12,000/12*3= 3,000

3 0
3 years ago
HELP PLEASE.
Verizon [17]
D notify the creditor and see if it can be changed and /or modified
6 0
3 years ago
Read 2 more answers
A university officer wants to know the proportion of registered students that spend more than 20 minutes to get to school. He se
vlada-n [284]

Answer:

1) We need a random sample. For this case we assume that the sample selected was obtained using the simple random sampling method.

2) We need to satisfy the following inequalities:

n\hat p =25*0.52= 13 \geq 10

n(1-\hat p) = 25*(1-0.52) =12 \geq 10

So then we satisfy this condition

3) 10% condition. For this case we assume that the random sample selected n represent less than 10% of the population size N . And for this case we can assume this condition.

So then since all the conditions are satisfied we can conclude that we can apply the normal approximation given by:

p \sim N (\hat p, \sqrt{\frac{\hat p (1-\hat p)}{n}})

So then the answer for this case would be:

a. Yes.

Explanation:

For this case we assume that the question is: If in the experiment described we can use the normal approximation for the proportion of interest.

For this case we have a sample of n =25

And we are interested in the proportion of registered students that spend more than 20 minutes to get to school.

X = 13 represent the number of students in the sample selected that have a time more than 20 min.

And then the estimated proportion of interest would be:

\hat p = \frac{X}{n}= \frac{13}{25}= 0.52

And we want to check if we can use the normal approximation given by:

p \sim N (\hat p, \sqrt{\frac{\hat p (1-\hat p)}{n}})

So in order to do this approximation we need to satisfy some conditions listed below:

1) We need a random sample. For this case we assume that the sample selected was obtained using the simple random sampling method.

2) We need to satisfy the following inequalities:

n\hat p =25*0.52= 13 \geq 10

n(1-\hat p) = 25*(1-0.52) =12 \geq 10

So then we satisfy this condition:

3) 10% condition. For this case we assume that the random sample selected n represent less than 10% of the population size N . And for this case we can assume this condition.

So then since all the conditions are satisfied we can conclude that we can apply the normal approximation given by:

p \sim N (\hat p, \sqrt{\frac{\hat p (1-\hat p)}{n}})

So then the answer for this case would be:

a. Yes.

3 0
3 years ago
The company can choose to buy a back-up machine for Step C for an additional $20,000. The back up would also have a reliability
Goshia [24]

The complete question is:

A certain company produces 10,000 tables per year in a three-step process. The three steps in the process employ machines with the reliabilities listed here:

Step A - 0.987 Step B – 0.979 Step C – 0.915

Answer:

New reliability= 0.9593 ~ 0.959

Explanation:

Reliability is used in manufacturing process to ensure that a process produces the same level of output consistently. A process is reliable if it achieves the same results everytime.

Reliability can be applied to individuals, data, processes, and products.

In this instance we are to calculate the new reliability of the backup system.

Reliability of step C is 0.915

New reliability= 1 - (1- 0.915)^2

New reliability= 0.992775

Multiply this value by the reliability in step A and B to get system reliability

System reliability= 0.992775 * 0.987 * 0.979

System reliability= 0.9593

7 0
3 years ago
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