X + y = 12
x - y = 4
From the second equation we can see that x = 4 + y
We can plug this into the first one and get:
4 + y + y = 12
4 + 2y = 12
2y = 12-4
2y = 8
y = 4
And then we can plug that into “x” and get that x = 4 + 4, or x=8
Answer:
A- sss
Step-by-step explanation:
Answer:
c.i^ 3
Step-by-step explanation:
i^7/i x i^3
i ^ 7 / i ^ 4
i^ 7 - 4
i^ 3
Answer:
First graph
Step-by-step explanation:
Here we have x ≥ 0, and y ≥ - 2, not x ≥ 0 and y ≥ 0. Thus, it doesn't restricts us fully to quadrant 1, but somewhat off considering y ≥ - 2. Now all we have to do is plot the following system of inequalities -
Convert each into slope intercept form -
Which should be bounded by a small region similar to graph 1! The shaded region represents each intersection with respect to their restriction to quadrant 1.
<u><em>Hope that helps!</em></u>