Speed = Distance/Time. Let speed be V, distance D and time T
a)Given: D₁ =45km, V₁=x km/h
V₁=D₁/T
V₁=45/T OR T= 45/V₁
b) Given : D₂ =48 km and V₂ = V₁ + 4 km/h
V₂ = 48/T, but V₂ = V₁+4, then:
V₁+4 = 48/T OR T=48/(V₁+4). Since Time is same, then we can write:
45/V₁ =48/(V₁+4), solve for V₁:
45V₁ + 180 = 48V₁
3V₁ =180 and V₁ = x = 60 km/h
From the given description it seems that the small shaded circle lies within the larger circle as shown in image below:
The probability that a point choosen at random lies within the shaded area = Area of shaded region / Total area of the bigger cricle
So,
Probability = 78.5/314 = 0.25
Thus there is 0.25 or 25% probability that the point chosen at random will lie inside the shaded region.
First, we need to solve the differential equation.

This a separable ODE. We can rewrite it like this:

Now we integrate both sides.

We get:

When we solve for y we get our solution:

To find out if we have any horizontal asymptotes we must find the limits as x goes to infinity and minus infinity.
It is easy to see that when x goes to minus infinity our function goes to zero.
When x goes to plus infinity we have the following:

When you are calculating limits like this you always look at the fastest growing function in denominator and numerator and then act like they are constants.
So our asymptote is at y=8.
Answer:
1. A
2. H
3.B
4. H
5. A
Those are the answers
Step-by-step explanation:
1. 30 - 2(-8)= 46
2. BODMAS applied 6-7 =-1
3. 45/-5=-9
4. Sum is h +73
5.BODMAS applied 60 /6 = 10