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lutik1710 [3]
4 years ago
5

Using the set {1,3,6,7,8,9} how many odd numbers can we construct between 100-999, if no element may be used more than once in a

number
Mathematics
1 answer:
nata0808 [166]4 years ago
3 0
Odd numbers end with 1 or 3 or 5 or 7 or 9

alrighty, the last number can be 1 or 3 or 7 or 9 (we aren't given 5 in the set)
4 choices for the last number

for the other 2 numbers, we can use any other numbers

6 numbers in the set
6 choices for the first digit
5 for the 2nd
4 for the 3rd digit


so there are 6*5*4 or 120 different odd numbers that can be constructed withthe given numbers in the set
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Consider the four points​ (10,10), (20,50),​ (40,20), and​ (50,80). the least squares line is modifyingabove y with caret equals
lesya [120]

Answer:

The y-intercept of the least squares line is 7 and slope of the line is 1.1. It means x and y are positively related.

Step-by-step explanation:

Least squares : It is an approach to find a regression line such that the sum of squares of residual(difference between estimated point on the line and data point) is minimum.

The given points are (10,10), (20,50),​ (40,20), and​ (50,80).

The least squares line is

y=7.0+1.1x             .... (1)

The general form of least squares line is

y=a+bx             .... (2)

where, a is y-intercept and b is slope of the line.

On comparing (1) and (2) we get

a=7.0,b=1.1

It means the y-intercept of the least squares line is 7 and slope of the line is 1.1.

Slope is positive it means x and y are positively related.

6 0
3 years ago
What is the equation of the line that contains the points (2,6) and (-2,4)
suter [353]

Answer:

y =1 /2 x+ 5

Step-by-step explanation:

3 0
4 years ago
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PLEASE HELP WITH MY MATH. SCIENTIFIC NOTATION PROBLEM.
nasty-shy [4]

Answer:


Step-by-step explanation:

a) 8.23 x 10^5 move the decimal over 5 places, 319000000 is 319 million move the decimal over until there is one number on the left side --> 3.19 x 10^8

b) 3.19 x 10^8 / 8.23 x 10^5 = 387.61 roughly 388 times larger

5 1
4 years ago
A student entering a doctoral program in educational psychology is required to select courses from the list of courses provided
SVEN [57.7K]

A) The possible three-course selections are as shown below.

B) The likelihood of selecting the combinations is 0.1 since there are 10 combinations in total.

<h3>How to solve probability combinations?</h3>

A combination operator can be used when we need to find the number of ways to select "k" items from a set of "n" items. It is also called a 'choose' operator where it is read as 'n choose k' and is represented and calculated as given below

From the choices given, there are 5 courses which are given below:

EPR 605

EPR 643

EPR 648

EPR 674

EPR 681

We need to find the combinations of 3 of these given 5 courses, which are given below (omitting the course code, EPR):

605-643-648

605-643-674

605-643-681

605-648-674

605-648-681

605-674-681

643-648-674

643-648-681

643-674-681

648-674-681

10 of the given choices of combinations are possible since they do not include a repeated course number.

The likelihood of selecting the combination of EPR 681, EPR 648, and EPR 605 is 0.1 since there are 10 combinations in total.

Complete question is;

A student entering a doctoral program in educational psychology is required to select three courses from the list of courses provided as part of his or her program. List all possible three-course selections. Comment on the likelihood that EPR 681, EPR 648, and EPR 605 will be selected. Select all the possible three-course selections below.

A. 648, 674, 605

B. 681, 648, 605

C. 681, 674, 605

D. 681, 681, 648

E. 674, 643, 674

F. 674, 605, 643

G. 681, 648, 674

H. 681, 681

I. 681, 648, 643

J. 648, 605, 643

K. 648, 674, 643

L. 681, 605, 643

M. 643, 694, 643

N. 681, 674, 643

Read more about Probability Combinations at; brainly.com/question/3901018

#SPJ1

8 0
2 years ago
If h(x) = 4x − 8 and j(x) = −x, solve h[j(3)] and select the correct answer below. (1 point) −20 −36 1 4
Nostrana [21]

Answer:

h[j(3)] = -20

Step-by-step explanation:

We need h(j(3)).  First find j(3)

j(x) = -x, so

j(3) = -(3) = -3

Now find h(-3)

h(x) = 4x - 8, so

h(-3) = 4(-3) - 8

  h(-3) = -12 - 8 = -20

So h[j(3)] = -20

3 0
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