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3 years ago

You bought a magazine for $7 and some candy bars for $4 each. You spent a total of $23. How many candy bars did you buy?

Mathematics

2 answers:

trasher [3.6K]3 years ago

8 0

Answer:

4 candy bars

Step-by-step explanation:

vesna_86 [32]3 years ago

8 0

Answer:

Step-by-step explanation:

because if you subtract 7 from 23 which is 16 then you divide that by the price of the candy 4, and 16/4 is 4 so you bought 4

Hope this helps:)

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The dimensions of a fish tank are 5 ft by 4 ft by 2 ft. There are 40 fish in the tank. What is the population density of the fis

Svet_ta [14]

My answer would be B

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3 years ago

he length of a rectangle is three times the width. The perimeter is 240 inches. Find the length and the width.

sammy [17]

Answer:

Length = 90 inch.

width = 30 inch

Let width of the rectangle = x inch.

So the length = 3x inch.

Perimeter = 2(length + width) = 2 (3x + x) = 8x.

So,

length = 3x = 3(30) = 90 inch.

width = x = 30 inch

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2 years ago

CAN SOMEONE HELP ME ANSWER THIS

jeka57 [31]

Answer:

It is 1/6

Step-by-step explanation:

This is because there are 6 sides to a dice and the number 3 is only on one of those sides. So, it is 1 in 6 or 1/6

8 0

2 years ago

Read 2 more answers

At 95% confidence, how large a sample should be taken to obtain a margin of error of 0.03 for the estimation of a population pro

Gnom [1K]

Answer:

A sample of 1068 is needed.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

At 95% confidence, how large a sample should be taken to obtain a margin of error of 0.03 for the estimation of a population proportion?

We need a sample of n.

n is found when M = 0.03.

We have no prior estimate of $\pi$ , so we use the worst case scenario, which is $\pi = 0.5$

Then

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.03 = 1.96\sqrt{\frac{0.5*0.5}{n}}$

$0.03\sqrt{n} = 1.96*0.5$

$\sqrt{n} = \frac{1.96*0.5}{0.03}$

$(\sqrt{n})^{2} = (\frac{1.96*0.5}{0.03})^{2}$

$n = 1067.11$

Rounding up

A sample of 1068 is needed.

8 0

2 years ago

Exponential growth/decay problem 1

RUDIKE [14]

Answer:

a) growth

b) $500

c) 6% = 0.06

d) $f(x)=500(1.06)^x$

e) $595.51

Step-by-step explanation:

Part (a)

Exponential GROWTH, since interest is applied to the account each year.

Part (b)

Initial amount = $500

Part (c)

Growth factor = 6% = 0.06 (in decimal form)

Part (d)

General form of exponential growth function:

$f(x)=a(1+r)^x$

where:

a = initial amount
r = rate of growth (in decimal form)
x = time (in years)

Given:

a = 500
r = 0.06

$\implies f(x)=500(1+0.06)^x$

$\implies f(x)=500(1.06)^x$

Part (e)

when x = 3

$\begin{aligned}\implies f(3) & =500(1.06)^3\\ & = 595.51\: \sf(nearest\:hundredth)\end{aligned}$

5 0

2 years ago