Malik considers the enlargement of the trapezoid. Not drawn to scale What is the correct cross product that he should use to sol
1 answer:
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Answer:
(1,4)
Step-by-step explanation:
Let's this of which is it's parent function.
How do we get to from there?
It has been reflected about the a-axis because of the - in front of the square root.
It has been shifted right 1 unit because of the -(1) in the square root.
It has been moved up 4 units because of the +4 outside the square root.
In general:
has the following transformations from the parent:
Moved right h units if h is positive.
Moved left h units if h is negative.
Moved up k units if k is positive.
Moved down k units if k is negative.
If is positive, it has not been reflected.
If is negative, it has been reflected about the x-axis.
also tells us about the stretching factor.
The parent function has a starting point at (0,0). Where does this point move on the new graph?
It new graphed was the parent function but reflected over x-axis and shifted right 1 unit and moved up 4 units.
So the new starting point is (0+1,0+4)=(1,4).
Answer:
4 cm
Step-by-step explanation:
The equation of a parabola with its vertex at the origin can be written as ...
y = 1/(4p)x^2
The problem statement tells us that one point on the parabola is (x, y) = (12, 9). We can put these values into the equation and solve for p, the distance from the focus to the vertex.
9 = 1/(4p)(12^2)
9×4/144 = 1/p = 1/4 . . . . . . . . multiply by the inverse of the coefficient of 1/p
Then p = 4, and the bulb is 4 cm from the vertex.
