Recall that
where 
is the angle between the vectors 
whose magnitudes are 
, respectively.
We have
Answer:
an = 2·2^(n-1)
Step-by-step explanation:
There are simple tests to determine whether a sequence is arithmetic or geometric. The test for an arithmetic sequence is to check to see if the differences between terms are the same. Here the differences are 2, 4, 8, so are not the same.
The test for a geometric sequence is to check to see if the ratios of terms are the same. Here, the ratios are ...
4/2 = 2
8/4 = 2
16/8 = 2
These ratios are all the same (they are "common"), so the sequence is geometric.
The general term of a geometric sequence with first term a1 and common ratio r is ...
an = a1·r^(n-1)
Filling in the values for this sequence, we find the general term to be ...
an = 2·2^(n-1)
Answer:
It equals 256 because 2x2x2x2x2x2x2x2= 256
Answer:
T
Step-by-step explanation:
Just did it
It's pretty much simple. Since we can factor a polynomial by its zeros, lets write one of degree nine :
X(X-1)(X-2)(X-3)(X-4)(X-5)(X+1)(X+2)(X+3)= X^9-9X^8+6X^7+126X^6-231X^5-441X^4+944X^3+324X^2-720X
This polynomial is of degree 9 and has exactly 5 strictly positive zeros : 1, 2, 3, 4, 5
And it has 3 negative zeros : - 1, -1, - 3
And it has 0 as a zero too.
There is also this one :
(X-1)(X-2)(X-3)(X-4)(X²+1)(X+1)(X+2)(X+3) = X^9-4X^8-13X^7+52X^6+35X^5-140X^4+13X^3-52X^2-36X+144
It has 4 positive zeros : 1, 2, 3, 4.
It has complex zeros : i and - i
3 negative zeros : - 1, - 2 , - 3
Good Luck
