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Llana [10]
3 years ago
15

How does doubling the base effect the perimeter of the triangle

Mathematics
1 answer:
Contact [7]3 years ago
6 0

i think it will make it smaller due to the base being longer which stretches out the two sides and makes less space inside of the triangle

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|3x-7| + 7 = 9 What is the first solution?<br><br> Plzzz help
posledela

Answer:

  • 3 and 5/3

Step-by-step explanation:

<u>Solving in steps:</u>

  • |3x-7| + 7 = 9
  • |3x-7|  = 2

<u>1. If 3x - 7 > 0</u>

  • 3x - 7 = 2
  • 3x = 9
  • x = 3

<u>2.  If 3x - 7 < 0</u>

  • 3x - 7 = -2
  • 3x = 5
  • x = 5/3
5 0
3 years ago
1 quarter 2 dimes 3 pennies how munch I have
vfiekz [6]
In total, you have 48 cents.
25+10+10+3= 48

Give 5 stars and brainliest answer if this helped please!<span>
</span>
8 0
3 years ago
I am VERY confused on this question. Can someone help me?
Iteru [2.4K]
Answer: z=67-at
————
a-45
6 0
3 years ago
I really need help with this one please
natka813 [3]

The distance from the sun is option 2 5.59 astronomical units.

Step-by-step explanation:

Step 1; To solve the question we need two variables. P which represents the number of years a planet takes to complete a revolution around the Sun. This is given as 13.2 years in the question so P = 13.2 years. The other variable is the distance between the planet and the sun in astronomical units. We need to determine the value of this using the given equation.

Step 2; So we have to calculate the value of 'a' in Kepler's equation. But the exponential power \frac{3}{2} is on the variable we need to find so we multiply both the sides by an exponential power of \frac{2}{3} to be able to calculate 'a'.

P =  a^{\frac{3}{2} }, P^{\frac{2}{3} } = a^{\frac{3}{2}*\frac{2}{3}  },  P^{\frac{2}{3} } = a, 13.2^{\frac{2}{3} } = a = 5.58533 astronomical units.

Rounding it over to nearest hundredth we get 5.59 astronomical units.

6 0
3 years ago
Help, please! 15 points! If you dont know dont answer please!
Luden [163]
The first thing to do is to sort the given data from smallest to largest. Doing so leads to this ordered list:
{13, 15, 15, 17, 18, 18, 20, 21, 21, 23, 26, 27, 28, 30, 32, 33, 37, 40}

From this list, we can see which values are between 10 and 19 (inclusive). Those values are {13, 15, 15, 17, 18, 18} which represents 6 values. So the first bar (for the "10-19" group) is going to be 6 units high.

The next group, in the "20-29" group, is this set of values {20, 21, 21, 23, 26, 27, 28} which is 7 items this time. The second bar is 7 units high.

The "30-39" bar will be 4 units high because there are 4 items in the set {30, 32, 33, 37}

There is only one person who is between 40 and 49, and that person is 40 years old. So the "40-49" group has a bar that has height of 1.

The final histogram and frequency chart is shown in the attached image. The frequency chart is optional, but it helps supplement the histogram in my opinion.

5 0
3 years ago
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