<h3>
Answer: C) 4/8 = 0.5</h3>
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Explanation:
The sine ratio involves the opposite over hypotenuse.
With respect to reference angle J, the opposite leg is the one furthest from the angle. So the opposite side is KL = 4. The hypotenuse is always the longest side, always opposite the 90 degree angle, so LJ = 8 is the hypotenuse.
sin(angle) = opposite/hypotenuse
sin(J) = KL/LJ
sin(J) = 4/8
sin(J) = 0.5
y = 9ln(x)
<span>y' = 9x^-1 =9/x</span>
y'' = -9x^-2 =-9/x^2
curvature k = |y''| / (1 + (y')^2)^(3/2)
<span>= |-9/x^2| / (1 + (9/x)^2)^(3/2)
= (9/x^2) / (1 + 81/x^2)^(3/2)
= (9/x^2) / [(1/x^3) (x^2 + 81)^(3/2)]
= 9x(x^2 + 81)^(-3/2).
To maximize the curvature, </span>
we find where k' = 0. <span>
k' = 9 * (x^2 + 81)^(-3/2) + 9x * -3x(x^2 + 81)^(-5/2)
...= 9(x^2 + 81)^(-5/2) [(x^2 + 81) - 3x^2]
...= 9(81 - 2x^2)/(x^2 + 81)^(5/2)
Setting k' = 0 yields x = ±9/√2.
Since k' < 0 for x < -9/√2 and k' > 0 for x >
-9/√2 (and less than 9/√2),
we have a minimum at x = -9/√2.
Since k' > 0 for x < 9/√2 (and greater than 9/√2) and
k' < 0 for x > 9/√2,
we have a maximum at x = 9/√2. </span>
x=9/√2=6.36
<span>y=9 ln(x)=9ln(6.36)=16.66</span>
the
answer is
(x,y)=(6.36,16.66)
Answer:
if he uses 1/2 for 2/3, then you can divide 2/3 and 1.2 by 2 to get the remaining soap needed to complete the wash
so to clean the last 1/3 of the car, he`ll use 1/4 of the remaining soap
the entire car needs <u><em>3/4 of a bottle of soap</em></u>
