Answer:
<em>The probability of exactly '4' success </em>
<em>P( X=4) = 0.2508</em>
Step-by-step explanation:
<u><em>Step(i)</em></u>:-
<em>Given sample size 'n' = 10</em>
<em>Given probability of success 'p' = 0.4</em>
q = 1 -p = 1 - 0.4 = 0.6
<u><em>Step(ii):-</em></u>
Let 'X' be the successes in binomial distribution
![P( x = r) = n_{C_{r} } p^{r} q^{n-r}](https://tex.z-dn.net/?f=P%28%20x%20%3D%20r%29%20%3D%20n_%7BC_%7Br%7D%20%7D%20p%5E%7Br%7D%20q%5E%7Bn-r%7D)
<em>The probability of exactly '4' success</em>
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<em>we will use factorial notation</em>
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<em>P( X=4) = 0.2508</em>
<u><em>conclusion:-</em></u>
<em>The probability of exactly '4' success </em>
<em>P( X=4) = 0.2508</em>
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