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DochEvi [55]
3 years ago
11

Solve for x in the diagram below

Mathematics
1 answer:
andre [41]3 years ago
3 0

Answer:

x= 20

Step-by-step explanation:

The sum of the three angles is 90 degrees

x+2x+x+10 = 90

Combine like terms

4x+10 = 90

Subtract 10

4x+10-10 = 90-10

4x= 80

Divide by 4

4x/4=80/4

x = 20

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Normal Distribution Problem. Porphyrin is a pigment in blood protoplasm and other body fluids that is significant in body energy
GarryVolchara [31]

Answer: a) 0.9332, b) 0.8944

Step-by-step explanation: the probability value attached to a z score is gotten by using a z distribution table.

The z score is gotten by making use of the formulae below

Z = x - u / σ

Where x = sample mean, u = population mean and σ = population standard deviation.

a)

For our question, u = 38, σ = 12, we are to look for the z score at z ≤ 56, that's x = 56

By substituting the parameters, we have that

z ≤ 56 = 56 - 38/ 12

z ≤ 56 = 18/12

z ≤ 56 = 1.5

To get the probabilistic value, we check the normal distribution table.

The table I'm using will be giving me probabilistic value towards the left of the area.

From the table, p ( z ≤ 56) = 0.9332.

b)

Z >23 = 23 - 38/ 12

Z >23 = - 15/ 12

Z >23 = - 1.25

The probability value of this z score is towards the right of the distribution but the table I'm using is only giving probability values towards the left.

Hence Z >23 = 1 - Z<23

From the table, Z<23 = 0.1056.

Z >23 = 1 - 0.1056

Z >23 = 0.8944

4 0
3 years ago
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A recipe calls for 4 carrots for every 2 cups of water. Which expression can be used to find the number of carrots needed
Arada [10]

Answer:

4 divided by 2 = 2 so 2carrots per cup of water

Step-by-step explanation:

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3 years ago
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Expansion Numerically Impractical. Show that the computation of an nth-order determinant by expansion involves multiplications,
posledela

Answer:

  • number of multiplies is n!
  • n=10, 3.6 ms
  • n=15, 21.8 min
  • n=20, 77.09 yr
  • n=25, 4.9×10^8 yr

Step-by-step explanation:

Expansion of a 2×2 determinant requires 2 multiplications. Expansion of an n×n determinant multiplies each of the n elements of a row or column by its (n-1)×(n-1) cofactor determinant. Then the number of multiplies is ...

  mpy[n] = n·mp[n-1]

  mpy[2] = 2

So, ...

  mpy[n] = n! . . . n ≥ 2

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If each multiplication takes 1 nanosecond, then a 10×10 matrix requires ...

  10! × 10^-9 s ≈ 0.0036288 s ≈ 0.004 s . . . for 10×10

Then the larger matrices take ...

  n=15, 15! × 10^-9 ≈ 1307.67 s ≈ 21.8 min

  n=20, 20! × 10^-9 ≈ 2.4329×10^9 s ≈ 77.09 years

  n=25, 25! × 10^-9 ≈ 1.55112×10^16 s ≈ 4.915×10^8 years

_____

For the shorter time periods (less than 100 years), we use 365.25 days per year.

For the longer time periods (more than 400 years), we use 365.2425 days per year.

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