WILL MARK. THE BRAINLEST!!!

Mathematics

2 answers:

AlekseyPX2 years ago

8 0

THE FIRST ONE IS RIGHT so yeah please mark me brainlest

11111nata11111 [884]2 years ago

6 0

(-4, 2), (-1, 2), and (-4, 0

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Help!!! please! im on my last try!

lilavasa [31]

Answer:

1. x = -3 or x = 5

2. x = 4 or x = 7

3. - 4 and 9

4. x = 4 or x = - 6

5. Unfortunately I got this one wrong, but put the answers above and you'll get an 80%

6 0

2 years ago

Read 2 more answers

Suppose a and b are the solutions to the quadratic equation 2x^2-3x-6=0. Find the value of (a+2)(b+2).

KonstantinChe [14]

Answer:

(a+2)(b+2) = 4

Step-by-step explanation:

We are given the following quadratic equation:

$2x^2-3x-6=0$

Let a a and b be the solution of the given quadratic equation.

Solving the equation:

$2x^2-3x-6=0\\\text{Using the quadratic formula}\\\\x = \dfrac{-b \pm \sqrt{b^2-4ac}}{2a}\\\\\text{Comparing the equation to }ax^2 + bx + c = 0\\\text{We have}\\a = 2\\b = -3\\c = -6\\x = \dfrac{3\pm \sqrt{9-4(2)(-6)}}{4} = \dfrac{3\pm \sqrt{57}}{4}\\\\a = \dfrac{3+\sqrt{57}}{4}, b = \dfrac{3-\sqrt{57}}{4}$

We have to find the value of (a+2)(b+2).

Putting the values:

$(a+2)(b+2)\\\\=\bigg(\dfrac{3+\sqrt{57}}{4}+2\bigg)\bigg(\dfrac{3-\sqrt{57}}{4}+2\bigg)\\\\=\bigg(\dfrac{11+\sqrt{57}}{4}\bigg)\bigg(\dfrac{11-\sqrt{57}}{4}\bigg)\\\\=\dfrac{121-57}{156} = \dfrac{64}{16} = 4$