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Nezavi [6.7K]
3 years ago
9

All of the dimensions of a triangle were multiplied by the same factor. If the base of the triangle went from 1 cm to 3 cm the a

rea of the triangle is multiplied by what number
Mathematics
2 answers:
Whitepunk [10]3 years ago
5 0
3 is the answer. hope it helps
SVEN [57.7K]3 years ago
5 0
It was multiplied by 3
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Vivid is a drummer for a band. She burns 756 calories in 3 hours. She burns the same number of calories each hour. How many calo
Anika [276]

Answer:

252 calories burned in 1 hour.

Step-by-step explanation:

She burns 756 calories in 3 hours.

She burns x calories in 1 hour

756/3 = x/1

756/3 = x

252 = x

So she burns 252 in 1 hour.

4 0
3 years ago
The figure below shows a shaded region and a nonshaded region. Angles in the figure that appear to be right angles are right ang
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<span>The "grey part" is 87 the rest is the "shaded part" together they add up to the big red rectangle = 128</span>
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3 years ago
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Chris earns $44 washing 4 cars. At this rate, how much does Chris earn washing 6 cars?
lana66690 [7]

Answer:

$66 for 6 cars.

Step-by-step explanation:

This is a rather simple problem. To find the answer you must divide 44/4= 11. Now knowing that Chris earns $11 per car if you multiply 11x6= 66 you can find out Chris makes $66 for 6 cars.

4 0
3 years ago
Simplify (9a2‐18ab + 9b2 -25c2) ÷ (3a–3b+5c) brainly​
Pani-rosa [81]

Answer:

3a-3b-5c

Step-by-step explanation:

((3a-3b)²-(5c)²)÷(3a-3b+5c)=((3a-3b-5c)(3a-3b+5c))÷(3a-3b+5c)=3a-3b-5c

7 0
3 years ago
The attractive electric force between point charges q and -2q has a magnitude of 2.2 N when the separation
swat32

Answer:

The Magnitude of charge = q = 15.47 micro coulomb  

Step-by-step explanation:

The attractive force between two points q and - 2 q = F = 2.2 Newton

The separation between two charges = 1.4 meters

Now from Coulomb's law = F = (k \frac{q1 q2}{r^{2}})  where k= 9 \times 10^{9} \frac{N m^{2}}{c^{2}}

So , 2.2 = 9 \times 10^{9} ( (\frac{(q) ( - 2q)}{1.4^{2}})

So , q ² = (\frac{0.479 \times 10^{-9}}{-2})

      For charge magnitude

   I.e q ² = 2.395 \times 10^{-10}

 so, q =  1.547 \times 10^{-5}

      q = 15.47 \times 10^{-6} c

Or,  q = 15.47 micro coulomb

Hence  the Magnitude of charge = q = 15.47 micro coulomb   Answer

4 0
4 years ago
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