How thick a layer would Earth form as it wraps around the neutron star’s surface is: 6.67 10⁻³ m.
<h3>Density of the Neutron star</h3>
Density
ρ = m / V
Where:
ρ= density
m = mass of the planet 5.98 10²⁴ km
V =volume of the spherical layer
Volume of a sphere
Volume = 4/3 π r³
Mass = 1.5 = 1.5 1,991 10³⁰
Mass= 2.99 10³⁰ kg
Density:
ρ = 2.99 10³⁰ / [4/3 π (10 10³)³]
ρ is = 7.13 10 17 kg / m³
V = 5.98 10²⁴ / 7.13 10¹⁷
V = 8,387 10⁶ m³
Thickness of the layer
V = 4π r² e
e = V / 4π r
e = 8,387 10⁶ / [4π (10 10³)²]
e = 6.67 10⁻³ m
Inconclusion how thick a layer would Earth form as it wraps around the neutron star’s surface is: 6.67 10⁻³ m.
Learn more about Density of the Neutron star here:brainly.com/question/15700804
Ummmmmmm I’m not sure just quizlet it. Trust me it helps me A lot
C. Use the values in the ratio table to write coordinate pairs for the points on the graph.
Thank you kind sir or miss
Answer:
The correct answer is D) by making sure that everyone could earn a living.
Explanation:
Hongwu, was the founder of the Ming Dynasty. He decided to make so reformations in the government of China that centralized much of decisions on him. He believed in the teachings of Confucious and the traditional rituals he taught. He followed the Mandate of Heaven and controlled every aspect of the Empire.