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2 years ago

13

Which expressions are equal to the expression _2.7 _ 16.4?

2 answers:

Genrish500 [490]2 years ago

8 0

This is just to easy the correct answer is A

nadya68 [22]2 years ago

4 0

The best and most correct answer among the choices provided by your question is the fourth choice or letter D.

The expression <span>_2.7 + (_16.4) would still be equal to </span><span>_2.7 _ 16.4 since the product of a positive and negative integer is also a negative number.</span>

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

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What is the average rate of change <br>y - 3 = -12 (x + 4)

vagabundo [1.1K]

Answer:

$- 12x$

Step-by-step explanation:

$y - 3 = - 12(x + 4) \\ y - 3 = - 12x - 48 \\ y = - 12x - 45$

Thr answer is the slope.

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2 years ago

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Alright this time can somebody help?

Deffense [45]

I'm pretty sure the answer is 232cm

11x8=88

88÷2=44

44x4=176

8x7= 56

176+56=232

Correct me if I'm wrong :)

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1 year ago

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- 3(x - 6) + 6 = 5x - 6. work<br>

MakcuM [25]

Answer:

= 15/4 as fraction

Step-by-step explanation:

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2 years ago

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Cubed root x cubed root x2

Yuki888 [10]

Answer:

Final answer is $\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=x$ .

Step-by-step explanation:

Given problem is $\sqrt[3]{x}\cdot\sqrt[3]{x^2}$ .

Now we need to simplify this problem.

$\sqrt[3]{x}\cdot\sqrt[3]{x^2}$

$\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}$

Apply formula

$\sqrt[n]{x^p}\cdot\sqrt[n]{x^q}=\sqrt[n]{x^{p+q}}$

so we get:

$\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=\sqrt[3]{x^{1+2}}$

$\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=\sqrt[3]{x^{3}}$

$\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=x$

Hence final answer is $\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=x$ .

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2 years ago

What is the COMMON DIFFERENCE of the following sequence: 10, 0, -10,

yulyashka [42]

10 is your common difference

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