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Ghella [55]
3 years ago
9

a cylinder has a surface area of 339 square centimeters and a radius of 6 centimeters. estimate the volume of the cylinder to th

e nearest whole number.
Mathematics
1 answer:
Naddika [18.5K]3 years ago
7 0
338.42 cm cubed.... there you go
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Paladinen [302]

Answer: the answer is either the first one or the third not exactly sure

Step-by-step explanation:

7 0
2 years ago
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Mark u brainliest and give 30 points.No random answers and pls give answers with explanation/steps or i will report u.​
blagie [28]

Answer:

I use equal signs throughout but they are meant to be less than or equal to signs.

s=sandwiches

4.5s+6 less than or equal to 50

The answer is s is less than or equal to 12

Step-by-step explanation:

Finding Inequality

1. we know everything costs 50 in total so that is on one side of the equal sign.

____=50

2. we know he already spent 6 dollars so the money he can spend is 6 dollars less.

____+6=50

3. Each sandwich costs 4.50 $ so how much money does he have left to spend? we figure that out by multiplying the price by the number of sandwiches.

4.5s+6=50

Solving

1. 4.5s-6=50

First use the addition property of equality and add 6 to both sides.

2. 4.5s=56

Then use the division property of equality and divide each side by 4.5

3. you get a decimal but since you can't buy half a sandwich the answer is

s is less than or equal to 12

3 0
3 years ago
These are similar<br> figures. Solve for x
Likurg_2 [28]

Answer:

x= the second one I hope I helped

8 0
2 years ago
Dartmouth Distribution Warehouse makes deliveries of a large number of products to its customers. It is known that 78% of all th
Alexxx [7]

Answer:

The probability that the value of P will be less than 0.81 is 0.7642.

Step-by-step explanation:

According to the Central limit theorem, if from an unknown population large samples of sizes <em>n</em> > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of this sampling distribution of sample proportion is:

 \mu_{\hat p}=p

The standard deviation of this sampling distribution of sample proportion is:

\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}

Given:

<em>n</em> = 100

<em>p</em> = 0.78

Since <em>n</em> = 100 > 30, according to the central limit theorem the sampling distribution of sample proportion follows a Normal distribution.

\hat p\sim N(\mu_{\hat p}=0.78, \sigma_{\hat p}=0.0414)

Compute the value of P(\hat p as follows:

P(\hat p

                  =P(Z

*Use a <em>z</em>-table for the probability.

Thus, the probability that the value of P will be less than 0.81 is 0.7642.

6 0
3 years ago
Alex bought a new boat with a 15-year loan at a 2.4% interest rate.
mixas84 [53]
<h3>Answer:   $44,097.56</h3>

==================================================

Work Shown:

L = loan amount

8456.40 = amount paid in interest

L+8456.40 = total amount paid back

15 years = 15*12 = 180 months

(L+8456.40)/180 = monthly payment

Well come back to this later, so let A = (L+8456.40)/180

------------------------------

Given the following

  • L = loan amount
  • r = 0.024 = annual interest rate in decimal form. This leads to i = r/12 = 0.024/12 = 0.002, which is the monthly interest rate in decimal form.
  • n = 180 months

We can form an expression to get us the monthly payment P.

We'll use this monthly payment formula.

P = (L*i)/( 1-(1+i)^(-n) )

So,

P = (L*i)/( 1-(1+i)^(-n) )

P = (L*0.002)/( 1-(1+0.002)^(-180) )

P = L*(0.002)/(0.30207279974017)

P = L*0.00662092052551

P = 0.00662092052551L

That represents the approximate monthly payment P based on the loan amount L, given the conditions listed above. This is equal to the value of A we found earlier, since that also represents the monthly payment.

Equate the two expressions and solve for L

0.00662092052551L = (L+8456.40)/180

180*0.00662092052551L = L+8456.40

1.1917656945918L = L+8456.40

1.1917656945918L-L = 8456.40

0.1917656945918L = 8456.40

L = 8456.40/0.1917656945918

L = 44097.564050758

L = 44097.56

The amount loaned to Alex to be able to purchase the boat was $44,097.56; this is the purchase price of the boat.

3 0
3 years ago
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