I don't really know what you're trying to ask because
x = -2 and x=6 are your roots.
But if you want to convert them back to their equation form,
get the other side of the equation to be 0.
x = 6
x - 6 = 0
x = -2
x + 2 = 0
so your original equation had something like (x+2)(x-6)
Answer:
yes
Step-by-step explanation:
three is a factor of 12 because you can multiply it by 4 and you get 12 (a factor is a number you can multiply by another to give you a product)
Answer:
(x + 2)(4x - 2).
Step-by-step explanation:
(x+2)(2x+1)+(x+2)(2x-3)
Note that (x + 2) is common to 2 parts of the expression. So we have:
(x + 2)(2x + 1 + 2x - 3)
= Ix + 2)(4x - 2)
Answer:
I think the correct answers are options 2 and 4.
so, as you can see above, the common ratio r = 1/2, now, what term is +4 anyway?
so is the 8th term, then, let's find the Sum of the first 8 terms.
![\bf S_8=512\left[ \cfrac{1-\left( \frac{1}{2} \right)^8}{1-\frac{1}{2}} \right]\implies S_8=512\left(\cfrac{1-\frac{1}{256}}{\frac{1}{2}} \right)\implies S_8=512\left(\cfrac{\frac{255}{256}}{\frac{1}{2}} \right)\\\\\\S_8=512\cdot \cfrac{255}{128}\implies S_8=1020](https://tex.z-dn.net/?f=%20%5Cbf%20S_8%3D512%5Cleft%5B%20%5Ccfrac%7B1-%5Cleft%28%20%5Cfrac%7B1%7D%7B2%7D%20%5Cright%29%5E8%7D%7B1-%5Cfrac%7B1%7D%7B2%7D%7D%20%5Cright%5D%5Cimplies%20S_8%3D512%5Cleft%28%5Ccfrac%7B1-%5Cfrac%7B1%7D%7B256%7D%7D%7B%5Cfrac%7B1%7D%7B2%7D%7D%20%20%5Cright%29%5Cimplies%20S_8%3D512%5Cleft%28%5Ccfrac%7B%5Cfrac%7B255%7D%7B256%7D%7D%7B%5Cfrac%7B1%7D%7B2%7D%7D%20%20%5Cright%29%5C%5C%5C%5C%5C%5CS_8%3D512%5Ccdot%20%5Ccfrac%7B255%7D%7B128%7D%5Cimplies%20S_8%3D1020%20)
