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satela [25.4K]
3 years ago
11

Can the sides of a triangle have lengths 6.2, 0.5, and 7.8? yes or no

Mathematics
1 answer:
Vitek1552 [10]3 years ago
4 0
No, it's not possible for the sides of a triangle to have those lengths.

According to the triangle inequality theorem, the sum of any two sides of the triangle has to be bigger than the last side. Let's test this.

6.2+7.8\ \textgreater \ 0.5

This inequality satisfies the triangle inequality theorem.

7.8+0.5\ \textgreater \ 6.2

This also satisfies the theorem.

6.2+0.5 \textless \ 7.8

Uh oh. This does not satisfy the triangle inequality theorem. Thus, it is not possible for a triangle to have these side lengths.
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Write an inequality to describe the region. the region between the yz-plane and the vertical plane x = 3
deff fn [24]

Write an inequality to describe the region is x < 0 < 3

Inequalities in three dimensions:

When an inequality representing a region in three dimensions contains only one of the three variables, then the other two variables have no restrictions. We use inequalities to describe solid regions in three dimensions.

Answers and Explanation:

The y z - plane is represented by the equation x = 0

As the region is between this plane and the vertical plane x = 3, we will get the inequality 0 < 0 < 3

Thus, the desired inequality is  

0 < 0 < 3.

Learn more about inequalities at:

brainly.com/question/14408811

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4 0
2 years ago
3. At Hector's Torta Shop, customers can order a steak, ham, or chicken sandwich. They can choose
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The slope of the line that passes through the points (-1,w) and (-10,4) is 1/9
forsale [732]

Answer:

c

Step-by-step explanation:

5 0
3 years ago
Need some geometry help
GenaCL600 [577]
Check the picture below.

that means

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angle BFC is 2(27) + 12 = 66

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6 0
3 years ago
Find the number of terms, n, in the arithmetic series whose first term is 13, the common difference is 7, and the sum is 2613.
siniylev [52]

Answer:

A

Step-by-step explanation:

Recall that the sum of an arithmetic series is given by:

\displaystyle S = \frac{n}{2}\left(a + x_n\right)

Where <em>n</em> is the number of terms, <em>a</em> is the first term, and <em>x</em>_<em>n</em> is the last term.

We know that the initial term <em>a</em> is 13, the common difference is 7, and the total sum is 2613. Since we want to find the number of terms, we want to find <em>n</em>.

First, find the last term. Recall that the direct formula for an arithmetic sequence is given by:

x_n=a+d(n-1)

Since the initial term is 13 and the common difference is 7:

x_n=13+7(n-1)

Substitute:

\displaystyle S = \frac{n}{2}\left(a + (13+7(n-1)\right)

We are given that the initial term is 13 and the sum is 2613. Substitute:

\displaystyle (2613)=\frac{n}{2}((13)+(13+7(n-1)))

Solve for <em>n</em>. Multiply both sides by two and combine like terms:

5226 = n(26+7(n-1))

Distribute:

5226 = n (26+7n-7)

Simplify:

5226 = 7n^2+19n

Isolate the equation:

7n^2+19n-5226=0

We can use the quadratic formula:

\displaystyle x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}

In this case, <em>a</em> = 7, <em>b</em> = 19, and <em>c</em> = -5226. Substitute:

\displaystyle x  =\frac{-(19)\pm\sqrt{(19)^2-4(7)(-5226)}}{2(7)}

Evaluate:

\displaystyle x = \frac{-19\pm\sqrt{146689}}{14} = \frac{-19\pm 383}{14}

Evaluate for each case:

\displaystyle x _ 1 = \frac{-19+383}{14} = 26\text{ or } x _ 2 = \frac{-19-383}{14}=-\frac{201}{7}

We can ignore the second solution since it is negative and non-natural.

Therefore, there are 26 terms in the arithmetic series.

Our answer is A.

6 0
3 years ago
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