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pochemuha
2 years ago
9

Nancy finds it difficult to locate emails in her Inbox. What action should she take to locate a particular type of email instant

ly?
A. group related emails in a folder
B. make a comprehensive task list
C. empty the Trash folder regularly
D. empty the Spam folder regularly
Computers and Technology
2 answers:
exis [7]2 years ago
4 0
Your answer would be A. Hope this helps!;)

Monica [59]2 years ago
4 0

Answer:

A. Group related emails in a folder.

Explanation:

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There are n poor college students who are renting two houses. For every pair of students pi and pj , the function d(pi , pj ) ou
Nuetrik [128]

Answer:

Here the given problem is modeled as a Graph problem.

Explanation:

Input:-  n, k and the function d(pi,pj) which outputs an integer between 1 and n2

Algorithm:-We model each student as a node. So, there would be n nodes. We make a foothold between two nodes u and v (where u and v denote the scholars pu and pv respectively) iff d(pu,pv) > k. Now, Let's call the graph G(V, E) where V is that the vertex set of the graph ( total vertices = n which is that the number of students), and E is that the edge set of the graph ( where two nodes have edges between them if and only the drama between them is bigger than k).

We now need to partition the nodes of the graph into two sets S1 and S2 such each node belongs to precisely one set and there's no edge between the nodes within the same set (if there's a foothold between any two nodes within the same set then meaning that the drama between them exceeds k which isn't allowed). S1 and S2 correspond to the partition of scholars into two buses.

The above formulation is akin to finding out if the graph G(V,E) is a bipartite graph. If the Graph G(V, E) is bipartite then we have a partition of the students into sets such that the total drama <= k else such a partition doesn't exist.

Now, finding whether a graph is bipartite or not is often found using BFS (Breadth First algorithm) in O(V+E) time. Since V = n and E = O(n2) , the worst-case time complexity of the BFS algorithm is O(n2). The pseudo-code is given as

PseudoCode:

// Input = n,k and a function d(pi,pj)

// Edges of a graph are represented as an adjacency list

1. Make V as a vertex set of n nodes.

2. for each vertex  u ∈ V

\rightarrow  for each vertex v ∈ V

\rightarrow\rightarrowif( d(pu, pj) > k )

\rightarrow\rightarrow\rightarrow add vertex u to Adj[v]   // Adj[v] represents adjacency list of v

\rightarrow\rightarrow\rightarrow add vertex v to Adj[u] // Adj[u] represents adjacency list of u

3.  bool visited[n] // visited[i] = true if the vertex i has been visited during BFS else false

4. for each vertex u ∈ V

\rightarrowvisited[u] = false

5. color[n] // color[i] is binary number used for 2-coloring the graph  

6. for each vertex u ∈ V  

\rightarrow if ( visited[u] == false)

\rightarrow\rightarrow color[u] = 0;

\rightarrow\rightarrow isbipartite = BFS(G,u,color,visited)  // if the vertices reachable from u form a bipartite graph, it returns true

\rightarrow\rightarrow if (isbipartite == false)

\rightarrow\rightarrow\rightarrow print " No solution exists "

\rightarrow\rightarrow\rightarrow exit(0)

7.  for each vertex u ∈V

\rightarrow if (color[u] == 0 )

\rightarrow\rightarrow print " Student u is assigned Bus 1"

\rightarrowelse

\rightarrow\rightarrow print " Student v is assigned Bus 2"

BFS(G,s,color,visited)  

1. color[s] = 0

2. visited[s] = true

3. Q = Ф // Q is a priority Queue

4. Q.push(s)

5. while Q != Ф {

\rightarrow u = Q.pop()

\rightarrow for each vertex v ∈ Adj[u]

\rightarrow\rightarrow if (visited[v] == false)

\rightarrow\rightarrow\rightarrow color[v] = (color[u] + 1) % 2

\rightarrow\rightarrow\rightarrow visited[v] = true

\rightarrow\rightarrow\rightarrow Q.push(v)

\rightarrow\rightarrow else

\rightarrow\rightarrow\rightarrow if (color[u] == color[v])

\rightarrow\rightarrow\rightarrow\rightarrow return false // vertex u and v had been assigned the same color so the graph is not bipartite

}

6. return true

3 0
3 years ago
30 point!! Looking at your Personal Fact Sheet, do you see any areas that may need improvement? In which areas do you have the m
Paul [167]
Can you please provide us with a photo of your personal fact sheet?
7 0
3 years ago
Read 2 more answers
What windows user interface can show you the programs that are currently active?
kirill115 [55]
Task manager
.............................
8 0
3 years ago
Select all the correct answers.
tino4ka555 [31]

Answer:

The correct options are:

include a numbered list of steps in the procedure

insert an image of the chocolate chip cookies  

email the recipe to her friend as an attachment

print a copy of the recipe to have handy while baking

Explanation:

Microsoft word provides several features which can be used to perform different tasks.

Lets look at each option one by one:

include a numbered list of steps in the procedure

The Bullets and Numbering" feature can be used for this purpose.

insert an image of the chocolate chip cookies

Can be inserted via "Add picture" Option

email the recipe to her friend as an attachment

"Share" option can be used for this purpose.

convert quantities measured in cups to metric units

Calculations cannot be done in MS word

print a copy of the recipe to have handy while baking

Print option can be used for this purpose.

Hence,

The correct options are:

include a numbered list of steps in the procedure

insert an image of the chocolate chip cookies  

email the recipe to her friend as an attachment

print a copy of the recipe to have handy while baking

7 0
2 years ago
If there is a need to write code in order to help the player move through the game which team member would create this code?
charle [14.2K]

Answer:

Run code, and then check the code

Explanation:

8 0
2 years ago
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