Respuesta:
5 L
Explicación:
Paso 1: Información provista
- Presión inicial (P₁): 1,5 atm
- Volumen inicial (V₁): 20 L
- Presión final (P₂): 6 atm
Paso 2: Calcular el volumen final del gas
Si asumimos temperatura constante y comportamiento ideal, podemos calcular el volumen final del gas (V₂) usando la Ley de Boyle.
P₁ × V₁ = P₂ × V₂
V₂ = P₁ × V₁ / P₂
V₂ = 1,5 atm × 20 L / 6 atm = 5 L
2.45 °C
From the Ideal gas law (Combined gas law)
PV/T = P'V'/T' .....eq 1
Where:
P - initial pressure
V - initial volume
T - initial temperature
P' - final pressure
V' - final volume
T' - final temperature.
To proceed we have to make T the subject from eq.1
Which is, T = P'V'T/PV.......eq.2
We have been provided with;
Standard temperature and pressure (STP)
P = 760 mm Hg (SP - Standard Pressure)
T = 273.15 K (ST - Standard Temperature)
V = 62.65 L
P' = 612.0 mm Hg
V' = 78.31 L
T' = ? (what we require)
Therefore, we substitute the values into eq.2
T' =
.
T' = 275.60 K
T = (275.60 - 273.15) ......To °C
T = 2.45 °C
>>>>> Answer
Have a nice studies.
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Answer:
In this case, ethanol's molecular mass is 46 g/mol. This means that in 1 mol of ethanol, there are 46 g, thus the term molecular mass and molar mass are often used interchangeably. The same is true of a mole. A mole of anything is 6.022 x 1023 of that item
Explanation: