<span>Specific gravity is the ratio of the density of a substance to the density of a reference substance; equivalently, it is the ratio of the mass of a substance to the mass of a reference substance for the same given volume.</span>
Answer:
14.336 g MnF₂
Explanation:
number of moles = mass / molecular weight
number of moles of MnI₂ = 55 / 309 = 0.178 moles
number of moles of F₂ = 55 / 38 = 1.447 moles
From the reaction and the number of moles calculated we deduce that the fluorine F₂ is a limiting reactant.
So:
if 13 moles of F₂ reacts to produce 2 moles of MnF₃
then 1.447 moles of F₂ reacts to produce X moles of MnF₃
X = (1.447 × 2) / 13 = 0.223 moles of MnF₃ (100% yield)
For 57.2% yield we have:
number of moles of MnF₃ = (57.2 / 100) × 0.223 = 0.128 moles
mass = number of moles × molecular weight
mass of MnF₃ = 0.128 × 112 = 14.336 g
Answer:
1.10 × 10⁻¹² m
General Formulas and Concepts:
<u>Chemistry - Atomic Structure</u>
Speed of Light = Wavelength times Frequency
Explanation:
<u>Step 1: Define</u>
ν = 2.73 × 10²⁰ Hz
<u>Step 2: Find wavelength</u>
3.0 × 10⁸ m/s = λ(2.73 × 10²⁰ Hz)
λ = 1.0989 × 10⁻¹² m
<u>Step 3: Check</u>
<em>We are given 3 sig figs. Follow sig fig rules.</em>
1.0989 × 10⁻¹² m ≈ 1.10 × 10⁻¹² m
Answer:
190 g
Explanation:
Knowing that:
- O₂ gas in air: 0.28 g O₂ / L of air
- Air inhaled at rest: 19.3 fl.oz. air / breath
- Human takes 20 breaths / min
The grams of oxygen gas (O₂) that a human at rest inhales in 1 hour (60 minutes) will be calculated as:
grams of O₂ = breaths in 1 hour * air inhaled per breath * amount of O₂ in air
grams of O₂ = 191.78 g
190 g of O₂ are inhaled in 1 hour (written in correct number of significant figures)
*In the calculation the amount of air inhaled per breath was converted from fl.oz. to Liters knowing that <em>1 L = 33.814 fl.oz.</em>
