Answer:
B the range, the x- and y-intercept
Step-by-step explanation:
the domain stays the same : all values of x are possible out of the interval (-infinity, +infinity).
but the range changes, as for the original function y could only have positive values - even for negative x.
the new function has a first term (with b) that can get very small for negative x, and then a subtraction of 2 makes the result negative.
the y-intercept (x=0) of the original function is simply y=1, as b⁰=1.
the y-intercept of the new function is definitely different, because the first term 3×(b¹) is larger than 3, because b is larger than 1. and a subtraction of 2 leads to a result larger than 1, which is different to 1.
the original function has no x-intercept (y=0), as this would happen only for x = -infinity. and that is not a valid value.
the new function has an x-intercept, because the y-values (range) go from negative to positive numbers. any continuous function like this must therefore have an x-intercept (again, y = the function result = 0)
Answer:
A) The model exists: f(x) = -3x^2 +4x -4
Step-by-step explanation:
A quadratic model will always exist for 3 given points, provided they are not on a line. In that case, a linear model is appropriate.
Here, the slope between -1 and 0 is positive, and the slope between 0 and 3 is negative. Thus, we know these points are not collinear, and a model must exist.
The model is most easily found using a quadratic regression tool. Such is shown in the attachment. It tells us that ...
f(x) = -3x^2 +4x -4
Answer:
The greatest common factor of 4 and 19 is 1
Step-by-step explanation:
Answer:
Step-by-step explanation:
You're looking for the circumference here, which is the distance around the outside of a circle. The formula is
C = πd or C = 2πr
Since we are given the diameter, we will use that one:
C = (3.14)(18) so
C = 56.5 feet
Given:
The system of inequalities:
To find:
Whether the points (–3,–2) and (3,2) are in the solution set of the given system of inequalities.
Solution:
A point is in the solution set of the given system of inequalities if it satisfies both inequalities.
Check for the point (-3,-2).
This statement is true.
This statement is also true.
Since the point (-3,-2) satisfies both inequalities, therefore (-3,-2) is in the solution set of the given system of inequalities.
Now, check for the point (3,2).
This statement is false because 
.
Since the point (3,2) does not satisfy the second inequality, therefore (3,2) is not in the solution set of the given system of inequalities.
