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GREYUIT [131]
3 years ago
8

Somebody please help me at this question !!!!! :)

Mathematics
1 answer:
koban [17]3 years ago
3 0
4.11 in both boxes.
This is because
  4.11
+4.11
---------
  8.22
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(4x^3 - x^2 +4x) + (x^3 -x^2 - 4x)
madreJ [45]

Answer:

5x³ - 2x²

Step-by-step explanation:

Step 1: Write out expression

4x³ - x² + 4x + x³ - x² - 4x

Step 2: Combine like terms (x³)

5x³ - x² + 4x - x² - 4x

Step 3: Combine like terms (x²)

5x³ - 2x² + 4x - 4x

Step 4: Combine like terms (x)

5x³ - 2x²

4 0
3 years ago
The graph represents the piecewise function:
svetoff [14.1K]

Answer:

x if -3is less than x is less than -1

5 is -1 is less than x is less than 1

Step-by-step explanation:

You find the slope of the line for the first piece when the x-values range from -3 to -1.

For the second piece, the line is y=5 because the line is horizontal.

5 0
3 years ago
Read 2 more answers
Help i need this so bad its due tomorrow
harina [27]

The area of the arrow it's 660 cm.

                   

8 0
3 years ago
This table shows information about the number of
tatiyna

Answer:

Mean number of holidays taken =26.6

Step-by-step explanation:

To find the mean,

We use Σfx/Σf

Σfx =150+234+189+84+0+60

=717

Σf= 6+9+7+3+0+2

=27

Σfx/Σf= 717/27

26.6

6 0
3 years ago
timothyis re-arranging his marbles collection. he has 5 identical blue marbles, five green and 3 black. he can fit excactly 5 ma
Lerok [7]
-- He must have at least one of each color in the case, so the first 3 of the 5 marbles in the case are  blue-green-black.

Now the rest of the collection consists of

                    4 blue
                    4 green
                    2 black

and there's space for 2 more marbles in the case.

So the question really asks:  "In how many ways can 2 marbles
be selected from 4 blue ones, 4 green ones, and 2 black ones ?"

-- Well, there are 10 marbles all together. 
So the first one chosen can be any one of the 10,
       and for each of those,
the second one can be any one of the remaining 9 .

Total number of ways to pick 2 out of the 10  =  (10 x 9)  =  90 ways.

-- BUT ... there are not nearly that many different combinations
to wind up with in the case.    

The first of the two picks can be any one of the 3 colors,
             and for each of those,
the second pick can also be any one of the 3 colors. 

So there are actually only 9 distinguishable ways (ways that
you can tell apart) to pick the last two marbles.
6 0
3 years ago
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